In many cases, elements that belong to the same group (vertical column) on the periodic table form ions with the same charge because they have the same number of valence electrons.
According to this equation:
AgCl(s) ↔ Ag+(aq) + Cl-(aq)
so K1 = [Ag+][Cl-]
when [Ag+] = [Cl-] we can assume both = X
and when we have X the solubility = 1.33 x 10^-5 mol / L
by substitution:
∴ K1 = X^2
= (1.33 x 10^-5)^2
= 1.77 x 10^-10
by using vant's Hoff equation:
ln(K2/K1) = (ΔH/R)*(1/T2-1/T1)
when ΔH = 65700 J / mol
R = 8.314
T1 = 25+273 = 298 K
T2 = 47.7 +273 =320.7
by substitution:
∴㏑(K2/1.77 x 10^-10) = (65700/8.314) * ( 1/320.7 - 1/ 298)
by solving for K2
∴K2 = 2.7 x 10^-11
and when K2 = X^2
∴ the solubility X = √(2.7 x 10^-11)
= 5.2 x 10^-6 mol/L
Cul (s) --> represents its state which means solid, Here Valency of copper is 1 so its cuprous.
<span>Fe2O3--> Ferric Oxide is a solid. Here valency of Fe is +3 so its Ferric </span>
<span>CoF2--> Cobalt Flouride is a solid</span>
<span>FeO --> Ferrous Oxide is a solid. Here valency of iron is +2 so its Ferrous. </span>
Answer:
1) 94.0° C, 2) 34.7°C
Explanation:
1)
Q=mcΔt° =mc(t2 - t1)
2350 J = 85.0 g* 0.385 J/(g*°C) *(t2 - 22.2°C)
t2 - 22.2°C = 71.81°C
t2 = 94.0° C
2)
Q=mcΔt° =mc(t2 - t1)
- 2070 J = 75.0 g * 0.903 J/(g*°C) *(t2 -65.3°C)
t2 - 65.3°C = - 30.56°C
t2 = 34.7°C
The species bonds with the most ionic character is the compound with elements that develop the higher electronegativity difference between each other.
the most ionic character had maximum EN.
EN is max for SiO2
hope this help
