Question

Drag the tiles to the correct boxes. Not all tiles will be used. The oxidation number of oxygen is -2, and that of chlorine is -1. Use this information to match the names of the compounds to their chemical formulas.
manganese(II) chloride
manganese(IV) chloride
manganese(II) oxide
manganese(IV) oxide

Answer 1

Answer:

1) Manganese(II)chloride :$MnCl_{2}$

2) Manganese(IV)chloride :$MnCl_{4}$

3) Manganese(II)oxide :$MnO$

4) Manganese(IV)oxide :$MnO_{2}$

Explanation:

It is given that:

Oxidation number of chlorine (Cl) = -1

Oxidation number of Oxygen (O) = -2

1) Manganese(II)chloride :

The oxidation number of manganese (Mn) is indicated by the roman numeral II = +2

Oxidation number of chlorine (Cl) = -1

Since the molecule is neutral the sum of charges on the cation (Mn) and anion (Cl) should be zero. This is possible only if one mole Mn combines with 2 moles Cl. Therefore, the chemical formula is $MnCl_{2}$

2) Manganese(IV)chloride :

The oxidation number of manganese (Mn) is indicated by the roman numeral IV = +4

Oxidation number of chlorine (Cl) = -1

Since the molecule is neutral the sum of charges on the cation (Mn) and anion (Cl) should be zero. This is possible only if one mole Mn combines with 4 moles Cl. Therefore, the chemical formula is $MnCl_{4}$

3) Manganese(II)oxide :

The oxidation number of manganese (Mn) is indicated by the roman numeral II = +2

Oxidation number of Oxygen (O) = -2

Since the molecule is neutral the sum of charges on the cation (Mn) and anion (O) should be zero. This is possible only if one mole Mn combines with 1 mole O. Therefore, the chemical formula is $MnO$

4) Manganese(IV)oxide :

The oxidation number of manganese (Mn) is indicated by the roman numeral IV = +4

Oxidation number of Oxygen (O) = -2

Since the molecule is neutral the sum of charges on the cation (Mn) and anion (O) should be zero. This is possible only if one mole Mn combines with 2 moles O. Therefore, the chemical formula is $MnO_{2}$

Answer 2

Answer:

That oxidation number of chlorine is -1 while that of oxygen is -2

Explanation:

When it comes to manganese chloride to stabilize the chlorine Ion. Two manganese ions shall be required. Hence the formula for the compound becomes $M_nCl_2$ while the formula for manganese (iv) chloride will be $M_nCl_4$ similarly.

When oxygen and magnesium oxide is considered the Two ions of Manganese will satisfy to ions of oxygen. Which cancels and becomes $M_nO$ while for manganese (iv) oxide  the formula becomes $M_nO_2$.