Answer:
1) Manganese(II)chloride :![MnCl_{2}](https://tex.z-dn.net/?f=MnCl_%7B2%7D)
2) Manganese(IV)chloride :![MnCl_{4}](https://tex.z-dn.net/?f=MnCl_%7B4%7D)
3) Manganese(II)oxide :![MnO](https://tex.z-dn.net/?f=MnO)
4) Manganese(IV)oxide :![MnO_{2}](https://tex.z-dn.net/?f=MnO_%7B2%7D)
Explanation:
It is given that:
Oxidation number of chlorine (Cl) = -1
Oxidation number of Oxygen (O) = -2
1) Manganese(II)chloride :
The oxidation number of manganese (Mn) is indicated by the roman numeral II = +2
Oxidation number of chlorine (Cl) = -1
Since the molecule is neutral the sum of charges on the cation (Mn) and anion (Cl) should be zero. This is possible only if one mole Mn combines with 2 moles Cl. Therefore, the chemical formula is ![MnCl_{2}](https://tex.z-dn.net/?f=MnCl_%7B2%7D)
2) Manganese(IV)chloride :
The oxidation number of manganese (Mn) is indicated by the roman numeral IV = +4
Oxidation number of chlorine (Cl) = -1
Since the molecule is neutral the sum of charges on the cation (Mn) and anion (Cl) should be zero. This is possible only if one mole Mn combines with 4 moles Cl. Therefore, the chemical formula is ![MnCl_{4}](https://tex.z-dn.net/?f=MnCl_%7B4%7D)
3) Manganese(II)oxide :
The oxidation number of manganese (Mn) is indicated by the roman numeral II = +2
Oxidation number of Oxygen (O) = -2
Since the molecule is neutral the sum of charges on the cation (Mn) and anion (O) should be zero. This is possible only if one mole Mn combines with 1 mole O. Therefore, the chemical formula is ![MnO](https://tex.z-dn.net/?f=MnO)
4) Manganese(IV)oxide :
The oxidation number of manganese (Mn) is indicated by the roman numeral IV = +4
Oxidation number of Oxygen (O) = -2
Since the molecule is neutral the sum of charges on the cation (Mn) and anion (O) should be zero. This is possible only if one mole Mn combines with 2 moles O. Therefore, the chemical formula is ![MnO_{2}](https://tex.z-dn.net/?f=MnO_%7B2%7D)