Answer:
please mark brainlest and it's Procedure 1: One of the products was a gas that escaped into the air.
Procedure 2: A gas from the air reacted with one of the other reactants
Explanation:
the gas ca evaporate so it would'nt be a or c and b dosent make sense.
Answer:
3.925 mol.
Explanation:
- From the balanced equation:
<em>2 Na₂O₂(s) + 2 H₂O(l) → 4 NaOH(s) + O₂(g)
,</em>
It is clear that 2 moles of Na₂O₂ react with 2 moles of H₂O to produce 4 moles of NaOH and 1 mole of O₂
.
<em>Using cross multiplication:</em>
4 moles of NaOH produced with → 1 mole of O₂
.
15.7 moles of NaOH produced with → ??? mole of O₂
.
<em>∴ The no. of moles of O₂ made =</em> (1 mole)(15.7 mole)/(4 mole) = <em>3.925 mol.</em>
The reaction will shift toward the reactants if the volume is cut in half.
<h3 /><h3>Reactants </h3>
The initial components of a chemical reaction are called reactants. Chemical bonds between reactants are broken and new ones are created in order to create products. Reactants and products are listed on the left and right sides, respectively, of the arrow in a chemical equation.
Substances on both sides of an arrow that points left and right are both reactants and products in a chemical process (the reaction proceeds in both directions simultaneously). A chemical equation that is balanced has the same amount of atoms of each element in the reactants and products. Around 1900–1920 is when the word "reactant" was first used. There are instances when the word "reagent" is interchangeable.
Learn more about reactants here:
brainly.com/question/17096236
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The answer is yes I believe so.
Answer:
Explanation:
Let's rewrite the given word equation in its chemical balanced equation representation:
1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: 
.
2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: 
.
3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: 
.
4. Ammonium nitride would require three amonium cations to balance the nitride anion: 
.
Let's write the balanced equation:
