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77julia77 [94]
4 years ago
9

What is.another name for a solution

Chemistry
1 answer:
prohojiy [21]4 years ago
8 0

Answer:

it can be resolution and remedy

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What are the possible values of ml for an electron in a d orbital?
spin [16.1K]
The correct answer for the question that is being presented above is this one: "-2, -1, 0, 1, 2." T<span>he possible values of ml for an electron in a d orbital are -2, -1, 0, 1, 2. </span>Since the allowed values for mℓ range from −ℓ to +ℓ, once you know the value for ℓ you know the values for mℓ."
3 0
3 years ago
In 2013 the world consumption of oil was estimated at 3.3 ´ 1010 barrels per year. The world reserves of oil in 2013 were estima
Serga [27]

Answer:

  about 37 years

Explanation:

If 100% of the estimated reserves are used at the current rate, it will take ...

  (1.234·10^12 bbl)/(3.3·10^10 bbl/yr) = 37.4 yr

It will take about 37 years to deplete the reserves.

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Your calculator can perform arithmetic using scientific notation.

3 0
3 years ago
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valina [46]
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7 0
3 years ago
Read 2 more answers
Caffeine, a molecule found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 10.0 g of caffeine pr
denis-greek [22]

Answer:

194 g/mol.

Explanation:

Hello,

In this case, one first must compute the mass of each element as shown below:

C=18.13gCO_2*\frac{12gC}{44gCO_2} =4.945gC\\H=4.639gH_2O*\frac{2.016gH}{18.0152gH_2O}=0.519gH\\N=2.885gN_2\\O=10.0g-4.945g-0.519g-2.885g=1.651gO

Next, the corresponding moles:

C=4.945gC*\frac{1molC}{12gC}=0.412mol\\H=0.519gH*\frac{1molH}{1gH}=0.519mol\\N=2.885gN*\frac{1molN}{14gN}=0.206molN\\O=1.648gO*\frac{1molO}{16gO} =0.103molO

Then, each element's subscripts is found to be:

C=\frac{0.412}{0.103}=4\\H=\frac{0.519}{0.103}=5\\N=\frac{0.206}{0.103} =2\\O=\frac{0.103}{0.103}=1

Therefore, the empirical formula is:

C_4H_5N_2O

Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:

C_8H_10N_4O_2

Which has a molar mass of 194 g/mol being correctly contained in the given interval.

Best regards.

8 0
3 years ago
Write the symbol for every chemical element that has an atomic number less than 13 and atomic mass greater than 19.3 u
emmainna [20.7K]

Answer:

The symbol of each element is, Ne, Na, Mg, and Al.

Explanation:

Below is the list of elements that has an atomic mass of less than 19.3 u.

The atomic mass of Neon is 20.1797 u and the atomic number is 10.

The atomic mass of Sodium is 22.989769 u and the atomic number is 11.

The atomic mass of Magnesium is 24.305 u and the atomic number is 12.

The atomic mass of Aluminium is 26.981539 u and the atomic number is 13.

Here, the symbol of each element is, Ne, Na, Mg, and Al.

3 0
4 years ago
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