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Tpy6a [65]
3 years ago
8

Select the fraction that is equivalent to 1/2

Chemistry
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

5/10,

10/20,

3/6

4/8

6/12

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PLEASE HELP!’ <br> DUE IN 10 MINS
Aleksandr [31]

Answer:

The products are SnPO4 and LiC2H3O2

Explanation:

The reactants are LiPO4 + Sn(C2H3O2)2

This is a double replacement reaction

So what you do is switch the elements the other way around.

To do that, all you have to do switch Sn with PO4 since Sn is a cation and PO4 is an anion.

Then you switch Li with C2H3O2 because Li is a cation and C2H3O2 is an anion.

After that, check the charges. PO4 has -3 charge

So just leave Sn the way it is without a subscript.

In word form, the product would be Tin(III) Phosphate

C2H3O2 has a -1 charge Li has a +1 charge

So leave both of them the way it is without any subscripts.

In word form, the product would be Lithium Acetate

7 0
3 years ago
How many mL of water to be added to 10 mL of 0.5M solution to make 0.2 M solution?
NikAS [45]

Answer:

0.7 is the right

Explanation:

3 0
3 years ago
What are some sources of error when testing for gases?​
Pavel [41]
The most important source of error in the measurement of CO2 elimination is rebreathing, which corresponds to bout 24 ml of end expiratory gas per breath with the standard Y-pieces and tubing.This problem may be decreased by the use of non-return valves in the Y-pieces.
8 0
4 years ago
The development of the cell theory involved ___________________________. A. different ideas from different scientists. B. the ef
pogonyaev

1. Different ideas from different scientists (such as schleiden and schwann)

2. B. Describe and examine cells

3. Sorry i don't remember this

hope this helps :)

6 0
4 years ago
the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig
Dmitrij [34]

Answer:

Faraday's constant will be smaller than it is supposed to be.

Explanation:

If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.

5 0
3 years ago
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