Answer:
Step-by-step explanation:
Given that there are six different toys and they are to be distributed to three different children.
The restraint here is each child gets atleast one toy.
Let us consider the situation as this.
Since each child has to get atleast one toy no of ways to distribute
any 3 toys to the three children each. This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways
So 3 toys to each one in 6x5x4 =120 ways
Now remaining 3 toys can be given to any child.
Hence remaining 3 toys can be distributed in 3x3x3 =27 ways
Total no of ways
= 120(27)
= 3240
It is 1082.
I hope it helps, you can do more on a calculator. :)))
Answer: what i would do is add a zero
Step-by-step explanation:
hope that help u have a wonderful day
Answer:
From least to greatest
23* 1/4, 23* 2/2, 23* 13/5
Explanation
In order to do this without multiplication, place the fractions in ascending order.
The denominators of these fractions have 20 as a common multiple.
2/2 • 10 = 20/20
1/4 • 5 = 5/20
13/5 • 4 = 52/20
From this it logically follows that the fractions in ascending order are:
1/4, 2/2, 13/5
Therefore the products in ascending order are:
23* 1/4, 23* 2/2, 23* 13/5
