The length of AQ is 4, the length of WQ is 12, 4 divided by 12 can be simplified as 1 divided by 3 so the answer is A. 1/3
K = ln (153/147)/7
k =
<span>
ln
(<span>
<span>
1.0408163265)/7
k = </span></span></span>0.040005334584
y(t) = a * e ^ k*t
y(2017) = 147 * e^ <span><span><span>0.040005334584
</span>
</span>
</span>
* 26
y(2017) = 147*e^
<span>
<span>
<span>
1.0401386992
</span>
</span>
</span>
y(2017) = 147*
<span>
<span>
<span>
2.8296094512
</span>
</span>
</span>
<span>y(2017) = 415.95 NOT very sure of that answer
</span>
Answer:
you use older of operations to solve this
