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3 years ago

8

Can someone plssssss helppppp

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Pepsi [2]3 years ago

7 0

Can you please be more specific

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How do you write 6.73 in scientific notation?

labwork [276]

Answer:

6.73 x 1 $0^{2}$

Step-by-step explanation:

4 0

4 years ago

AC =<br> Round your answer to the nearest hundredth.<br> 5<br> ?<br> 35<br> B

Bingel [31]

Answer:2.87

Step-by-step explanation:sin =opp/hyp

Sin 35=ac/5

Cross multiply

Sin 35 x 5 = ac

0.5736 x 5 =ac

2.868=ac

Ac=2.87

3 0

3 years ago

Find the area of each parallelogram<br><br> Please help with these thank you

hammer [34]

A=8
B=10

Hope this helps :D

4 0

3 years ago

Mr. Vader wasted 1/4of his laundry his son washed 2/5of it how much of the laundry still needs to be washed

Alik [6]

7/20 still needs to be washed.

4 0

3 years ago

In △ABC, point D∈ AC with AD:DC=4:3, point E∈ BC so that BE:EC=1:5. If ACDE=5 in2, find ABDC, AABD, and AABC.

Kaylis [27]

Answer:

ar ΔBDC=6 $in^2$

ar ΔABD=8 $in^2$

ar ΔABC=14 $in^2$

Explanation:

Please take a look of attach figure.

We are given area of triangle ar ΔCDE=5 $in^2$

ar ΔCDE= $\frac{1}{2}\times DN\times EC$ ------------(1)

ar ΔBDE= $\frac{1}{2}\times DN\times BE$ ------------(2)

Divide eq(2) by eq(1) and we get,

$\frac{ar\ ΔBDE}{ar\ ΔCDE}=\frac{BE}{EC}$

$\frac{ar\ ΔBDE}{5}=\frac{1}{5}$

So, ar ΔBDE=1 $in^2$

ar ΔBDC=ar ΔBDE+ ar ΔCDE

ar ΔBDC=1+5 = 6 $in^2$

Similarly,

$\frac{ar\ ΔABD}{ar\ ΔBDC}=\frac{AD}{DC}$

$\frac{ar\ ΔABD}{6}=\frac{4}{3}$

ar ΔABD=8 $in^2$

ar ΔABC=ar ΔABD + ar ΔBDC

ar ΔABC=8+6 = 14 $in^2$

6 0

3 years ago