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Mama L [17]
3 years ago
9

A student is standing a distance of 4 m from the school bell. If the student moves to a distance 20 m away, what fraction of the

original intensity of the bell’s sound will the student hear?
Mathematics
1 answer:
Neporo4naja [7]3 years ago
6 0

Answer:

Fraction=1/5=0.2

Step-by-step explanation:

If the student is 4m away from the school bell and moves 20m away, it means that he is 5 times more distant from the school bell and therefore should listen 5 times less, that is, 1/5 of the original sound.

Note: this as long as the initial environment conditions of 4m are the same at 20m

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After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only three women among the last
mixer [17]

Answer:

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

Step-by-step explanation:

For each employee hired, the are only two possible outcomes. Either it is a man, or it is a woman. The probability of a person hired being a man or a woman is independent of any other person. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

21 new employees.

This means that n = 21

She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.

This means that p = 0.5

Help her address the charge of gender discrimination by finding the probability of getting three or fewer women when 21 people are hired.

This is

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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P(X = 2) = C_{21,2}.(0.5)^{2}.(0.5)^{19} = 0.0001

P(X = 3) = C_{21,3}.(0.5)^{3}.(0.5)^{18} = 0.0006

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.00001 + 0.0001 + 0.0006 = 0.00071

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

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