X=2 because first you have to combine like terms. Than you have to bring the Varible on one side. Finally you solve for the Varible and you get the answer2.
X = -6y - 12
4x + 5y =-39
4x + 5y = -39
-4(-6y - 12) + 5y = -39
-4(-6y) + 4(12) + 5y = -39
24y + 48 + 5y = -39
29y + 48 = -39
29y = -87
y = -3
x = -6y - 12
x = -6(-3) - 12
x = 28 - 12
x = 6
(x, y) = (6, -3)
Answer:
<em>I </em>=2000(0.075)4= $600
Step-by-step explanation:
Let y be the total cost and x be the miles taken:
y = 0.30x + 35
35 is a fixed cost. No matter how many miles you drive the car you will still need to pay $35
.30 is a cost that depends on the miles taken (x).
Hope this helped!
~Just a girl in love with Shawn Mendes
1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:
<span>
A=(b1+b2/2)h
</span><span>
A is the area of the trapezoid.
</span><span> b1 is the larger base of the trapezoid (b1=16-4=12 ft).
</span><span> b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
</span><span> h is the height of the trapezoid (h=12-4=8 ft)
</span><span>
2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:
</span><span>
A=(b1+b2/2)h
</span><span> A=(12 ft+6 ft/2)(8 ft)
</span><span> A=9 ftx8ft
</span><span> A=72 ft²
</span><span>
3. </span><span>The length of fencing is:</span> a²=b²+c² a=√b²+c² a=√(8 ft)²+(6 ft)² a=10 ft Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft
