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Makovka662 [10]
3 years ago
12

What is the fractional equivalent of 0.2323?

Mathematics
2 answers:
saul85 [17]3 years ago
5 0
The fractional <span>equivalent of 0.2323 is 2323/1000 or you can multiply both the numerator and denominator with the same number and the resulting fraction would still be equal to it. This number is called as a rational number since it can be written in terms of fraction.</span>
nekit [7.7K]3 years ago
3 0
2323/1000=4646/2000
<span> is the fractional equivalent of 0.2323</span>
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The answer is<em> </em><em>D</em>.

I hope this helps



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What is the problem of 200 and 400
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By switching service providers, a family’s monthly bill decreased from $57 in May to
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In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF.
gulaghasi [49]

Answer:

2.7 square inch

Step-by-step explanation:

\triangle BAC \sim \triangle EDF... (Given) \\

\therefore By area of similar triangle theorem:

\frac{A(\triangle BAC)}{A(\triangle EDF)} = \frac{BC^2}{EF^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{3^2}{2^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{9}{4} \\\\\therefore A(\triangle EDF) = \frac{4\times 6}{9} \\\\\therefore A(\triangle EDF) = \frac{24}{9} \\\\\therefore A(\triangle EDF) = 2.6667\\\\\huge \purple {\boxed {\therefore A(\triangle EDF) = 2.7\: in^2}}

7 0
4 years ago
Consider the following sets of sample data: A: $30,500, $27,500, $31,200, $24,000, $27,100, $28,600, $39,100, $36,900, $35,000,
Alecsey [184]

Answer:

CV=0.2 ---- dataset 1

CV = 7.2 --- dataset 2

Step-by-step explanation:

Given

A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,33100

B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11

Required

The coefficient of variation of each

<u>Dataset A</u>

Calculate the mean

\mu = \frac{\sum x}{n}

\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}\mu = \frac{418900}{14}

\mu = 29921.43

Next, calculate the standard deviation using:

\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}

So, we have:

\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}

\sigma= \sqrt{\frac{487723571.42857}{14}}

\sigma= \sqrt{34837397.959184}

\sigma= 5902.32

So, the coefficient of variation is:

CV=\frac{\sigma}{\mu}

CV=\frac{5902.32}{29921.43}

CV=0.2 --- approximated

<u>Dataset B</u>

Calculate the mean

\mu = \frac{\sum x}{n}

\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}

\mu = \frac{46.79}{11}

\mu = 4.25

Next, calculate the standard deviation using:

\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}

\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}

\sigma = \sqrt{\frac{3.859}{11}}

\sigma = \sqrt{0.35081818181}

\sigma = 0.593

So, the coefficient of variation is:

CV=\frac{\sigma}{\mu}

CV = \frac{4.25}{0.5903}

CV = 7.2 -- approximated

3 0
3 years ago
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