All categories

3 years ago

What is the fractional equivalent of 0.2323?

2 answers:

5 0

The fractional <span>equivalent of 0.2323 is 2323/1000 or you can multiply both the numerator and denominator with the same number and the resulting fraction would still be equal to it. This number is called as a rational number since it can be written in terms of fraction.</span>

nekit [7.7K]3 years ago

3 0

2323/1000=4646/2000
<span> is the fractional equivalent of 0.2323</span>

You might be interested in

How can you tell that the inequality 3t+1> 3t + 2

lutik1710 [3]

Answer:

see below

Step-by-step explanation:

3t+1> 3t + 2

Subtract 3t from each side

1>2

This is never true so there is no solution

Since the variable terms are the same, we only have to look at the constants

6 0

3 years ago

Adam plans to choose a video game from a section of the store where everything is 75% off. He writes the expression d−0.75d to f

alekssr [168]

Answer:

is 0.75d becase the missing numbers should be the same number

5 0

3 years ago

Read 2 more answers

If ln(4x+y)=2x-3,then dy/dx=

Viktor [21]

$\ln(4x+y)=2x-3$

Differentiate both sides wrt $x$ :

$\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}$

By the chain rule, we get

$\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2$

$\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2$

Solve for $\frac{\mathrm dy}{\mathrm dx}$ :

$4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y$

$\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}$

4 0

3 years ago

PLLLLLLZZZZ HELP!! MULTIPLE CHOICE!!

liubo4ka [24]

First, set 2x+7 equal to 3x-7 since they are the same angle due to the parallel lines.

2x+7=3x-7
x=14

Then, since 2x+7 and 12y+1 equals 180, put it together to find y:

(2x+7)+(12y+1)=180
(2(14)+7)+(12y+1)=180
12y+1=145
12y=144
y=12

So, x=14 and y=12. Your answer should be C!

5 0

3 years ago

Please help me answer the question in the picture!

Slav-nsk [51]

Answer:

x = 5 units.

Step-by-step explanation:

In a parallelogram. diagonals bisect each other.

This means $\overline{CE} = \overline{BE}$ .