Answer:
x ≥ 7
Step-by-step explanation:
|x - 7| = x - 7
A. For each absolute, find the intervals
x - 7 ≥ 0 x - 7 < 0
x ≥ 7 x < 7
If x ≥ 7, |x - 7| = x - 7 > 0.
If x < 7, |x - 7| = x - 7 < 0. No solution.
B. Solve for x < 7
Rewrite |x - 7| = x - 7 as
+(x - 7) = x - 7
x - 7 = x - 7
-x + 14 = x
14 = 2x
x = 7
7 ≮7. No solution
C. Solve for x ≥ 7
Rewrite |x - 7| = x - 7 as
+(x - 7) = x - 7
x - 7 = x - 7
True for all x.
D. Merge overlapping intervals
No solution or x ≥ 7
⇒ x ≥ 7
The diagram below shows that the graphs of y = |x - 7| (blue) and of y = x - 7 (dashed red) coincide only when x ≥ 7.
" Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).1. = [3x + 2] + [4 – 5x] = 3x + 2 + 4 – 5x. = 3x – 5x + 2 + 4. = –2x + 6. (f – g)(x) 2. = f (x) – g(x)= [3x + 2] – [4 – 5x] = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x– 2. 3. ...= (3x + 2)(4 – 5x) = 12x + 8 – 15x2 – 10x. = –15x2 + 2x + 8. " - Google
<u>Shorter term class:</u>
You pay $200 for 54 classes in total. So,
dollars per class (rounded to 3 decimal places)
<u>Longer term class:</u>
You pay $350 for 108 classes in total, So,
dollars per class (rounded to 3 decimal places)
Hence, by taking longer term classes, you save around
dollars.
Rounding to 2 decimal places, you save $0.46 per class.
ANSWER: You save $0.46 per class.
Answer:
35 lbs is the final weight
Step-by-step explanation:
20 +23 = 43 lbs
Then they had to remove 8 lbs
43 - 8 =35
35 lbs is the final weight
Step-by-step explanation:
both halves of a diagonal must be equal.
so,
8b - 30 = 6b + 6
2b = 36
b = 18
and
9a - 13 = 5a + 5
4a = 18
a = 18/4 = 4.5