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3 years ago

If you can, please help answer this algebra question.

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

5 0

Answer:

R: {-7,-2,3,8}

Step-by-step explanation:

The range is the output values of the function

The values or 8,3,-2,-7

We put them in order from smallest to largest

R: {-7,-2,3,8}

olga2289 [7]3 years ago

4 0

Answer:

2nd option would be the answer

{y:y=-7,-2,3,8}

Step-by-step explanation:

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Jet001 [13]

Answer:

Step-by-step explanation:

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2 years ago

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Express 96 as the product of prime factors need it asap plzz write the method too

Murrr4er [49]

Given:

The given number is:

$96$

To find:

The product of prime factors of given number.

Solution:

We have,

$96$

The prime factors of given number are:

2 | 96

2 | 48

2 | 24

2 | 12

2 | 6

3 | 3

| 1

So, 96 can be written as:

$96=2\times 2\times 2\times 2\times 2\times 3$

Therefore, the 96 as the product of prime factors is $96=2\times 2\times 2\times 2\times 2\times 3$ .

3 0

2 years ago

How can you simplify No viruses please

Alexeev081 [22]

Answer:

In order to simplify a fraction there must be:

A number that will divide evenly into both the numerator and denominator so it can be reduced, or

The numerator must be greater than the denominator, (an improper fraction), so it can be converted to a mixed number.

Step-by-step explanation:

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5 0

3 years ago

The function g(x) = 12,500(0.91)x represents the value of a piece of farm equipment after x years. Approximately when will its v

topjm [15]

Answer:

B. 7.3 years

Step-by-step explanation:

The question is wrong. The correct function is :

$g(x)=12500(0.91)^{x}$

We have the function $g(x)$ that represents the value of a piece of farm equipment after $x$ years.

This means that when $x=0$ its original value is :

$g(0)=12500(0.91)^{0}=12500$

Now we want to calculate approximately when will its value be half its original value. Then, we write :

$\frac{12500}{2}=6250$

$6250$ is half of its original value. We need to find $x$ that satisfies the following equation :

$g(x)=6250=12500(0.91)^{x}$

Solving for $x$ :

$6250=12500(0.91)^{x}$ ⇒

$0.5=(0.91)^{x}$

Now we apply natural logarithm to each side of the equation :

$ln(0.5)=ln[(0.91)^{x}]$

Using logarithm properties :

$ln(0.5)=ln[(0.91)^{x}]$ ⇒

$ln(0.5)=x[ln(0.91)]$

$x=\frac{ln(0.5)}{ln(0.91)}$ ⇒

$x$ ≅ $7.3496$

The correct option is B. 7.3 years

4 0

3 years ago

Please help! Will give brainliest! Don't give a like.

den301095 [7]

9514 1404 393

Answer:

fraction
denominator
product
numerator

Step-by-step explanation:

When you multiply a fraction by a whole number, the denominator in the product is the same as the denominator of the fraction. The numerator in the product is the product of the whole number and the numerator of the fraction.

That's the rule. It is derived from the fact that multiplication indicates repeated addition.

$\dfrac{2}{7}\times3=\dfrac{2}{7}+\dfrac{2}{7}+\dfrac{2}{7}=\dfrac{2+2+2}{7}=\dfrac{2\times3}{7}\qquad\text{for example}$

7 0

3 years ago