What Global Positioning system signals can you tell
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the <u>average powe</u><u>r</u> output of the sun is <u>3.8 × </u><u> W</u> given that about 1350 w/m2 reaches the upper atmosphere of the earth.
As we know intensity falling over a surface is equal to Energy falling per unit area per unit volume.
I =
Since Power is equal to energy/time
I = power/area
or
Power = Intensity × area
Now, Distance from Sun to Earth , r = 149.6 × m
So, Surface area of the sphere of radius is:
A = 4 π
= 4 × 3.14 × (149.6 × )²
= 2.81 × m²
Thus Average Power output of the sun will be:
P = 1350 × 2.81 ×
= 3.7935 ×
P = 3.8 × W
So the average power output of the sun is 3.8 × W.
If you need to learn more about about the average power of a resistor, click here.
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