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Sedaia [141]
3 years ago
13

Find the domain of F(x-2)=4-3x-x^2

Mathematics
1 answer:
brilliants [131]3 years ago
3 0

The domain of any polynomial is "the set of all real numbers."  

I think you may have mistyped your function, meaning F(x)=4-3x-x^2.  But either way, F(x-2)=4-3x-x^2 and F(x) are polynomials, and so their domains are "the set of all real numbers."


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It would be impossible because u don't have 3
8 0
3 years ago
Read 2 more answers
For what value of a is (a,9) a solution for the equation y=2x+1?
Ivahew [28]

Answer:

Step-by-step explanation:

(a,9).......we dont know " a " (or x) but we do know y...it is 9

so sub in 9 for y and solve for x

y = 2x + 1

9 = 2x + 1

9 - 1 = 2x

8 = 2x

8/2 = x

4 = x <======= ur answer is D

5 0
3 years ago
When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic
Elanso [62]

Answer:

95% Confidence interval for the mean

142.8 \leq\mu\leq158.4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

cf=\sqrt{\frac{N-n}{N-1} }

The standard deviation can be estimated as

\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963

The 95% confidence interval has a z value of 1.96, so it becomes:

M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4

5 0
3 years ago
Mason collects seashells each year on the family trip to Sanibel Island. He has 90 whelks, which is 37.5% of his
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6 0
2 years ago
Please give me the right answer?
baherus [9]

(5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m)

P = 53/10 + 5 3/10 + 5 3/10 + 5 3/10

P = 53/10 + 53/10 + 5 3/10 + 5 3/10

P = 53/5 + 5 3/10 + 5 3/10

P = 53/5 + 53/10 + 5 3/10

P = 159/10 + 5 3/10

P = 159/10 + 53/10

P = 106/5

P = 21 1/5 meters

Answer: 21 1/5 meters (Decimal: 21.2m)

Hope that helps!!!! Have a great day!!!! : )

7 0
3 years ago
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