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Monica [59]
3 years ago
8

Think of the last five things you read. Now think of a type of reading you havent done recenty

Physics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

1) Half Girlfriend

2) I am Malala

3) Diamond fire

4)I too had a love story

5)Your Dream are Now Mine

Explanation:

I don't have a same pattern to read but mostly of romantic and fiction. I read less autobiographies but when I read I am Malala , it was an inspiring one.My favorite type of reading is romantic types and least favorite is non fiction especially History

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3. A 64 lb weight stretches a spring 4 ft in equilibrium. The weight is initially displaced 6 inches above equilibrium and given
Damm [24]

Answer:

Explanation:

the solution is given in the attached pictures

6 0
3 years ago
Differentiate gravitational force and acceleration due to gravity​
julia-pushkina [17]

Answer:

I hope this answer is correct

Explanation:

Difference Between Gravitation and Gravity

Gravitation is referred to the force acting between two bodies which can be represented as the F=(GM1M2)/R2 which means gravitation force is proportional to the product of the masses of the object 1 and object 2 and is inversely proportional to the square of the distance between them. The gravitational force between earth and any object is known as gravity.

Difference Between Gravitation and Gravity

Gravitation Gravity

It is a universal force It is not a universal force

It is a weak force It is a strong force

The force is F=(GM1M2)/R2 (G= gravitational constant) The force is F=mg (g=acceleration due to gravity)

The direction of gravitational force lies in the radial direction from the masses The direction of the force of gravity is along the line joining the earth’s center and the center of the body. Its direction is towards the center of the earth.

The force can be 0 when the separation between bodies is infinity The force of gravity can be 0 at the center of the earth

It requires two masses It requires only one mass

These were some difference between Gravitation and Gravity. If you wish to find out more, download BYJU’S The Learning App.

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Gravity Acceleration Due to Gravity

8 0
4 years ago
How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?
Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

Q = ms\Delta T

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

Q = 3(385)(1085 - 83)

Q = 1157310 J

Q = 1157.3 kJ

now in order to melt the copper we know the heat required is

Q = mL

here we know that

L = 205 kJ/kg

now from above formula

Q = 3(205) kJ

Q = 615 kJ

now total heat required will be

Q = 1157.3 kJ + 615 kJ

Q = 1772.3 kJ

As we know that

1 Cal = 4.18 kJ

now we have

Q = \frac{1772.3}{4.18} = 430 KCal

6 0
3 years ago
Which of the following statements is NOT correct?
Flauer [41]
The answer is
D:if the
6 0
3 years ago
Synchronous communications satellites are placed in a circular orbit that is 3.59 107 m above the surface of the earth. What is
suter [353]

Answer: 0.223 m/s^{2}

Explanation:

We can solve this with the Law of Universal Gravitation and knowing the acceleration due gravity g of an object above the surface of the planet decreases with the distance (height) of this object from the center of the planet.

Well, according to the law of universal gravitation:

F=G\frac{m_{E}m}{r^2}  (1)

Where:

F is the module of the force exerted between both bodies

G=6.67(10)^{-11}\frac{m^{3}}{kgs^{2}} is the gravitational constant

m_{E}=5.98(10)^{24} kg is the mass of the Earth

m are the mass of each communications satellite

r=R_{E}+h is the distance between the center of the Earth and the satellite

R_{E}=6.38(10)^{6} m is the radius of the Earth

h=3.59(10)^{7} m is the height of the satellite, measured from the Earth's surface

On the other hand, we know according to <u>Newton's 2nd law of motion:</u>

F=mg  (2)

Combining (1) and (2):

G\frac{m_{E}m}{r^2}=mg  (3)

Isolating g:

g=\frac{G M_{E}}{r^2}  (4)

Remembering r=R_{E}+h:

g=\frac{G M_{E}}{(R_{E}+h)^2}  (5)

g=\frac{(6.67(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24} kg)}{(6.38(10)^{6} m+3.59(10)^{7} m)^2}  

Finally:

g=0.223 m/s^{2}  

5 0
3 years ago
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