2 years ago

A. 24.89 B. 25.89 C. 17.74 D. 19.73

Physics

1 answer:

Veronika [31]2 years ago

5 0

Answer: D

Explanation:

Just did it got an 100

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CAN SOMEONE PLEASE TELL ME WHAT THIS WHEEL IS CALLED.WILL GIVE BRAINLIEST

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3 years ago

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Recalculate 100 km/h to m/s

qwelly [4]

= 27.777

Explanation:

A kilometer has 1,000 meters, and an hour has 3,600 seconds, so 100 kilometers per hour is: 100 x 1,000 / 3,600 = 27.777... m/s.

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3 years ago

A 70.9-kg boy and a 43.2-kg girl, both wearing skates face each other at rest on a skating rink. The boy pushes the girl, sendin

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Answer:

Explanation:

Given

mass of boy $m_b=70.9\ kg$

mass of girl $m_g=43.2\ kg$

speed of girl after push $v_g=4.64\ m/s$

Suppose speed of boy after push is $v_b$

initially momentum of system is zero so final momentum is also zero because momentum is conserved

$P_i=P=f$

$0=m_b\cdot v_b+m_g\cdot v_g$

$v_b=-\frac{m_g}{m_b}\times v_g$

$v_b=-\frac{43.2}{70.9}\times 4.64$

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2 years ago

A 4kg brick is dropped from the top of a building whose hight is 30m.what is the velocity with which it reaches the ground

miss Akunina [59]

Answer:

=24.25 ^−1

Explanation:

Let and be initial and final velocity of the body respectively,

be acceleration due to gravity ( 9.8^−2 ), ℎ be the height of the body.

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ℎ=30

we know that, ^2−^ 2=2ℎ

^2=2∗9.8∗30

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3 years ago

A 235.0 g metal block absorbs 2.44 × 103 J of heat to raise its temperature by 35 K. What is the specific heat of the metal? Sho

andrew-mc [135]

When an object absorbs an amount of energy equal to Q, its temperature raises by $\Delta T$ following the formula
$Q=m C_s \Delta T$
where m is the mass of the object and $C_s$ is the specific heat capacity of the material.

In our problem, we have $Q=2.44 \cdot 10^3 J$ , $m=235.0 g$ and $\Delta T=35 K$ , so we can re-arrange the formula and substitute the numbers to find the specific heat capacity of the metal:
$C_s = \frac{Q}{m \Delta T}= \frac{2.44 \cdot 10^3 J}{(235.0 g)(35 K)}=0.297 J g^{-1} K^{-1}$

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3 years ago