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babymother [125]

3 years ago

11

Need help have to turn in tomorrow and having a really hard time understanding

1 answer:

e-lub [12.9K]3 years ago

7 0

For 23, you only know 1 set of numbers, which is the hypotenuse. The numbers are 5 and 10. The difference is that the second triangle is 2 times more than the 1st. So the answer is 3 times 2 and 4 times 2 which is 6 and 8, or A. For 24, notice the second figure is 360 less than the first. The 3rd is 180 less than the 2nd. So it only makes sense that the 4th would be 90 less than the 3rd. So D is the most probable answer.

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8(7 + 23) = 8(7) + 8(?)

34kurt

Answer: 23

When using multiplication with brackets, you multiply the number by all the numbers within the bracket before adding them together.

Therefore when it is 8(7 + 23) it basically means: 8(7) + 8(23)

7 0

3 years ago

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Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

2 years ago

-Continued answer to my last question

Natalka [10]

Answer:

It's the first graph.

Step-by-step explanation:

The data points resemble the data in the table more than the second.

6 0

3 years ago

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Sorry I’m not very good with this type of math.

kaheart [24]

Answer:

91

Step-by-step explanation:

5 0

3 years ago

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What happens when the multiplicity of a real root is odd?

Mariulka [41]

Answer:

A: the graph will cross the x-axis

7 0

3 years ago

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