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AleksandrR [38]
3 years ago
13

Suppose that atom x undergoes radioactive decay that results in atom y. If y has a larger atomic number than x, which type of ra

dioactive decay occured? Alpha decay, Beta decay, Gamma decay, or Delta decay??
Chemistry
1 answer:
Zanzabum3 years ago
4 0
Beta decay and I have to write something else to reach the min 20 words so I’m writing this to inform you why a am writing this
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Can you please answer number 8 thanks
MAXImum [283]
A day is added to February every four tears as a corrective measure. The Earth does not exactly revolve around the sun for 365 days. There is a small offset that is corrected by adding a day to February. This happens every four years and it is called Leap year.
4 0
3 years ago
During this reaction, P4 + 5O2 → P4O10, 1.5 moles of product were made in seconds. What is the rate of reaction? 0.011 g/min 210
Ivanshal [37]

The answer is: the rate of reaction is 850 g/min.

n(P₄O₁₀) = 1.5 mol; amount of product.

M(P₄O₁₀) = 283.9 g/mol; molar mass of phosphorus(V) oxide.

m(P₄O₁₀) = n(P₄O₁₀) · M(P₄O₁₀).

m(P₄O₁₀) = 1.5 mol · 283.9 g/mol.

m(P₄O₁₀) = 425.85 g in 30 seconds.

Make proportion: 425 g : 30 s = m(P₄O₁₀) : 60 s.

m(P₄O₁₀) = 850 g in 60 s.

7 0
3 years ago
Read 2 more answers
How many moles of ethylene (C2H4) can react with 12.9 liters of oxygen gas at 1.2 atmospheres and 297 Kelvin? C2H4(g) + 3O2(g) y
7nadin3 [17]
1) Convert 12.9 liters of Oxygen to mol at the given conditions:

PV = nRT ⇒ n = PV/RT

n = [1.2atm*12.9 l] / [0.082 atm l /K mol * 297K]

n = 0.636 mol of O2

2) use the stoichiometry derived from the balanced chemical equation

 1mol C2H4 / 3  mol O2 =  x mol C2H4 / 0.636 mol O2

x = 0.636 / 3 mol O2 = 0.212 mol O2.

Answer: 0.212 mol O2
5 0
3 years ago
The work function for metallic potassium is 2.3 eV. Calculate the velocity in km/s for electrons ejected from a metallic potassi
mote1985 [20]

Answer:

932.44 km/s

Explanation:

Given that:

The work function of the magnesium = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, work function = 2.3\times 1.6022\times 10^{-19}\ J=3.68506\times 10^{-19}\ J

Using the equation for photoelectric effect as:

E=\psi _0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

Applying the equation as:

\frac {h\times c}{\lambda}=\psi _0+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

m is the mass of electron having value 9.11\times 10^{-31}\ kg

\lambda is the wavelength of the light being bombarded

\psi _0=Work\ function

v is the velocity of electron

Given, \lambda=260\ nm=260\times 10^{-9}\ m

Thus, applying values as:

\frac{6.626\times 10^{-34}\times 3\times 10^8}{260\times 10^{-9}}=3.68506\times 10^{-19}+\frac{1}{2}\times 9.11\times 10^{-31}\times v^2

3.68506\times \:10^{-19}+\frac{1}{2}\times \:9.11\times \:10^{-31}v^2=\frac{6.626\times \:10^{-34}\times \:3\times \:10^8}{260\times \:10^{-9}}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=7.64538\times 10^{-19}-3.68506\times 10^{-19}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=3.96032462\times 10^{-19}

v^2=0.869446\times 10^{12}

v = 9.3244 × 10⁵ m/s

Also, 1 m = 0.001 km

<u>So, v = 932.44 km/s</u>

5 0
3 years ago
Please help I need a 100
svlad2 [7]

your answer would be C.

6 0
3 years ago
Read 2 more answers
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