Question

Hydrogenation of double and triple bonds is an important industrial process. Calculate (in kJ/mole) the standard enthalpy change ΔH° for the hydrogenation of ethyne (acetylene) to ethane. Just enter a number (no units).

Answer 1

Answer:

$\Delta _RH=-310.53kJ/mol$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$C_2H_2(g)+2H_2(g)\rightarrow C_2H_6(g)$

Thus, the standard enthalpies of formation are:

$\Delta _fH_{C_2H_2}=226.73kJ/mol\\\Delta _fH_{H_2}=0kJ/mol\\\Delta _fH_{C_2H_6}=-83.8 kJ/mol$

Hence, the standard enthalpy of reaction becomes:

$\Delta _RH=-83.8kJ/mol-0kJ/mol-226.73kJ/mol\\\Delta _RH=-310.53kJ/mol$

Best regards.