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expeople1 [14]
3 years ago
12

Una molécula de O2 esta hecho de​

Chemistry
1 answer:
Airida [17]3 years ago
8 0
Dos átomos de oxígeno
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Type the correct answer in the box. Express your answer to two significant figures. An industrial vat contains 650 grams of soli
nikklg [1K]

88.98 %

The Balance Chemical Equation is as follow,

                                  2 HCl + Pb(NO₃)₂     →    2 HNO₃ + PbCl₂

According to equation,

          331.2 g (1 mole) Pb(NO₃)₂ produces  =  278.1 g (1 mole) PbCl₂

So,

                 870 g of Pb(NO₃)₂ will produce  =  X g of PbCl₂

Solving for X,

                     X  =  (870 g × 278.1 g) ÷ 331.2 g

                     X  =  730.5 g of PbCl₂

Therefore,

               Theoretical Yield =  730.5 g

Also as given,

                Actual Yield =  650 g

So using following formula for percentage yield,

                        %age Yield  =  (Actual Yield / Theoretical Yield) × 100

Putting values,

                        %age Yield  =  (650 g / 730.5 g) × 100

                        %age Yield  =  88.98 %

Brianliest please and thank you.

6 0
3 years ago
use the periodic table to select the element from the drop-down menu that has the correct relative electronegativity.
Bumek [7]
You need to list the elements but remember that fluorine has the highest electronegativity out of the entire periodic table
6 0
3 years ago
Read 2 more answers
Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i
swat32

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg  

7 0
3 years ago
What are the effects of viagra?
koban [17]
<span><span>An erection that will not go away (priapism). 
S</span><span>udden vision loss in one or both eyes 
</span>Sudden hearing decrease or hearing loss.</span>
7 0
3 years ago
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Help pls ill give extra points
r-ruslan [8.4K]

Explanation:

im sorry but it depends on what the diagram looks like for the problem

3 0
2 years ago
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