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Solnce55 [7]
4 years ago
15

Rita needs to solve 3/4 divided by 2/3, she plans to multiply 3/4 times 3/2 will Rita’s strategy work

Mathematics
1 answer:
zlopas [31]4 years ago
6 0

Answer:

Yes, I think so!

Step-by-step explanation:

3*3=9

4*2=8

So i will be 9/8

Hope this helps!

(pls mark brainiest!)

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If,<br> 2=5<br> 3=10<br> 4=17<br> 5=??
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WILL MARK BRAINLIEST! PLEASE HELP MEH!<br><br><br> Find the area
grigory [225]
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6 0
3 years ago
If
inna [77]

Answer:

i can only show exaples hope these helps

Step-by-step explanation:

One-to-one

Suppose f : A ! B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c 2 A with

a 6= c, we are guaranteed that f(a) 6= f(c).

Example. f : R ! R where f(x) = x2 is not one-to-one because 3 6= 3

and yet f(3) = f(3) since f(3) and f(3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(x) in more than one point,

then f(x) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate – for example, (2, 3) and

(4, 3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two di↵erent objects in the domain to the same object

of the target.

If every horizontal line in R2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : R ! R where f(x) = x2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

90

Inverse Functions

One-to-one

Suppose f : A ⇥ B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c ⇤ A with

a ⌅= c, we are guaranteed that f(a) ⌅= f(c).

Example. f : R ⇥ R where f(x) = x2 is not one-to-one because 3 ⌅= 3

and yet f(3) = f(3) since f(3) and f(3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(x) in more than one point,

then f(x) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate – for example, (2, 3) and

(4, 3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two dierent objects in the domain to the same object

of the target.

If every horizontal line in R2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : R ⇥ R where f(x) = x2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

66

Inverse Functions

One-to-one

Suppose f : A —* B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c e A with

a ~ c, we are guaranteed that f(a) $ f(c).

Example. f : IR —* JR where f(x) = x2 is not one-to-one because 3 ~ —3

and yet f(3) = f(—3) since f(3) and f(—3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(.x) in more than one point,

then f(z) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate — for example, (2,3) and

(4,3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two different objects in the domain to the same object

of the target.

If every horizontal line in JR2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : JR —, R where f(z) = z2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

\~. )L2

66

Below is the graph of g : R ! R where g(x) = x3. Any horizontal line that

could be drawn would intersect the graph of g in at most one point, so g is

one-to-one.

Onto

Suppose f : A ! B is a function. We call f onto if the range of f equals

8 0
3 years ago
HELP!!
Lady_Fox [76]

Answer:

Step-by-step explanation:

5 0
2 years ago
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