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Solnce55 [7]
3 years ago
9

Given the function rule f(x) = x² – 4x + 3, what is the output of f(–3)? (1 point)

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

24

Step-by-step explanation:

To calculate the output substitute x = - 3 into f(x), that is

f(- 3) = (- 3)² - 4(- 3) + 3 = 9 + 12 + 3 = 24 ← output

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In a game the player wins if he rolls a 6 on a number cube .if the number cube is rolled 18 times then what is the reasonable
sp2606 [1]
<h2>Answer:</h2>

Prediction for the number of unsuccessful rolls is 15.

<h2>Step-by-step explanation:</h2>

There is \frac{1}{6} chance of rolling number 6 on the cube. If we want to find out what is the prediction for rolling number 6 in 18 rolls, we need to multiply 6*\frac{1}{6} which is 3. So if we roll a cube 18 times, we will probably got number 6 three times. When we subtract 3 from 18 (18-3), we get 15. That is the answer to your question.

I hope I helped you. I will be really happy, If you mark my answer as the brainliest.Your David

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4 years ago
the function f(x)=2•5x can be used to represent the curve through the points (1,10) (2,50) and (3,250). What is the multiplicati
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The answer would be 5
8 0
3 years ago
Read 2 more answers
In triangle abc angle b is equal to 45 , a is equal to 24ft, and c is equal to 30ft. find b
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If angle a is 24ft and angle c is 30ft, then angle b is 126ft.
3 0
3 years ago
Given the following statistics for women over the age of 50 entering our medical clinic: 1% actually have breast cancer 90% of t
vazorg [7]

Answer: 91.2%

Step-by-step explanation:

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4 0
4 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
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