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3 years ago

What point names the ordered pair (3, -5)?

Mathematics

2 answers:

satela [25.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

you go 3 to the right because is a positive 3 then you go down 5 times because its negative and theres your answer

gregori [183]3 years ago

5 0

Answer:

Step-by-step explanation:

We start at the origin (we the axis cross)

We go three units to the right, then 5 units down.

We end up at the point D

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Use the cross product property to solve each equation: 5/7 = x/9

enot [183]

Answer:

x = 45/7

Step-by-step explanation:

$\frac{5}{7} =\frac{x}{9}$

Here, you can more easily see what the fractions look like.

In order to cross-multiply, you have to multiply 5 with 9, and 7 with x.

45 = 7x

Then, you isolate x by dividing 7 on both sides:

45/7 = x

Hope I helped :)

8 0

3 years ago

Round 6.73524 to the Nearest hundredth. 6.73 6.734 6.735 6.74

docker41 [41]

Answer:

The answer is 6.74

5 0

3 years ago

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Maurice has 76 postcards in all. The ratio of the number of postcards he has received to the number of postcards he has bought i

nexus9112 [7]

Answer:

50 but if its not an estimate 50.6 i would try 50 first

Step-by-step explanation:

also brainiest plz

4 0

2 years ago

How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$

b) In this case we need to solve a first order ordinary differential equation of the following form:

$\frac{dy}{dx} + p(x) \cdot y = q(x)$ (2)

Where:

$p(x)$ - Integrating factor
$q(x)$ - Particular function

Hence, the ordinary differential equation is equivalent to this form:

$\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x}$ (3)

The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ . $\blacksquare$

The solution for (2) is presented below:

$y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C$ (4)

Where $C$ is the integration constant.

If we know that $p(x) = -\frac{1}{x}$ and $q(x) = x^{2} + \frac{1}{x}$ , then the solution of the ordinary differential equation is:

$y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C$

$y = x\int {x} \, dx + x\int\, dx + C$

$y = \frac{x^{3}}{2}+x^{2}+C$

If we know that $x = 1$ and $y = -1$ , then the particular solution is:

$y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ . $\blacksquare$

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0

2 years ago

$28 lunch ; 15% tip total cost to the nearest cent

blsea [12.9K]

To find the tip:
28 x 15/100 = 4.2 dollars
Add the tip to the cost of the lunch gives us the total cost:
28 + 4.2 = 32.2

5 0

3 years ago

Read 2 more answers