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Anestetic [448]
3 years ago
12

Describe the graph of y=1/2x-10 -3 comapred to the graph of y= 1/x

Mathematics
1 answer:
saw5 [17]3 years ago
7 0

The parent function is:

$y=\frac{1}{x}

The transformed function is:

$y=\frac{1}{2 x-10}-3

$y=\frac{1}{2(x-5)}-3

$y=\frac{1}{2}\left(\frac{1}{x-5}\right)-3

Comparison of simplified transformed function with the parent function:

  • The function multiplying by a number indicates dilation.
  • The function is being compressed in vertical direction by a factor of 2 if the number lies between 0 and 1.
  • Subtracting a number from x indicates a horizontal shift towards right.
  • That is the parent function is transformed 5 units to right.
  • Subtracting a number from the function indicates a downward shift.
  • That is the parent function is transformed 3 units down.

Hence the graph of y=\frac{1}{2 x-10}-3 is the graph of y=\frac{1}{x} stretched vertically, shifted right by 10 unit and shifted 3 unit down.

The image of the graph is attached below.

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If 2/11x-2=-15/7 then​
yarga [219]

Answer:

X= -15/7

Step-by-step explanation:

search up on photomath it's really useful

5 0
3 years ago
P and W are twice-differentiable functions with P(7)=2(W(7)). The line y=9+2.5(x-7) is tangent to the graph of P at x=7. The lin
fiasKO [112]

Using the product rule, we have

m(x) = x W(x) \implies m'(x) = xW'(x) + W(x)

so that

m'(7) = 7W'(7) + W(7)

The equation of the tangent line to <em>W(x)</em> at <em>x</em> = 7 has all the information we need to determine <em>m'</em> (7).

When <em>x</em> = 7, the tangent line intersects with the graph of <em>W(x)</em>, and

<em>y</em> = 4.5 + 2 (7 - 7)   ==>   <em>y</em> = 4.5

means that this intersection occurs at the point (7, 4.5), and this in turn means <em>W</em> (7) = 4.5.

The slope of this tangent line is 2, so <em>W'</em> (7) = 2.

Then

m'(7) = 7\cdot2 + 4.5 = \boxed{18.5}

4 0
3 years ago
Matt and Ming are selling fruit for a school fundraiser. Customers can buy small boxes and large boxes of apples. Matt sold 5 sm
BartSMP [9]

Mind helping me on this? brainly.com/question/23506969 thanks!

7 0
3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
What is -18.278-(6.8)
Nastasia [14]

your answer would be -25.078

i hope this helps.!

5 0
3 years ago
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