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3 years ago

8x + 1 ≤ 9 + 6x ≤ 5 + 10x

Mathematics

1 answer:

Andreas93 [3]3 years ago

3 0

Answer:

x = -19

Step-by-step explanation:

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-7q + 12r = 3q - 4r what dose r equal

Elanso [62]

Answer:

r = 5y/8

Step-by-step explanation:

isolate the variable by dividing each side by factors that contain the variable.

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3 years ago

Jim had 5/7 of a pound of candy. she ate 1 3/4 of that candy. how many pounds of candy did he eat?

harkovskaia [24]

What she ate is
(13/4)×(5/7)
65/28 pounfs of candy

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3 years ago

explain how to use estimation to help find the product of two decimals. give an example with both estimated and actual answer

Marrrta [24]

To find the product of a reasonable estimate of two decimal numbers, round each decimals to the nearest whole number and then perform the multiplication.

For example:

3.2 x 5.7

Estimated answer

3.2 will be rounded down to 3 and 5.7 will be rounded up to 6

⇒ 3 x 6 = 18

Actual Answer

3.2 x 5.7

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7 0

1 year ago

What is the value of y in the solution to the system of equations?x y = 12x – 3y = –30

zhenek [66]

X + y = 12 . . . . . . . . (1)
x - 3y = -30 . . . . . . . (2)
(1) - (2): 4y = 42
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8 0

3 years ago

Read 2 more answers

A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

$P(x)=2x+\frac{4500000}{x}$

Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0

3 years ago