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3 years ago

2. The coach of a cricket team buys 3 bats and 6 balls for 3900. Later, she buys another

Mathematics

2 answers:

Marta_Voda [28]3 years ago

8 0

Answer:

1x + 3y = 1300

Step-by-step explanation:

ollegr [7]3 years ago

5 0

Step-by-step explanation:

variable x = bats

variable y = balls

3x + 6y = 3900

1x + 3y = 1300

I believe this is what they meant by represent it algebraically, but I'm not sure exactly what your class is learning right now. Geometrically, I do not know what they mean. I hope this helps you in some way

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A man drives from home to the store, shops, and then drives back home. Click on the graph until the graph that best represents t

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It'll be the third one because he stops to shop for a bit, then goes straight home.

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3 years ago

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Suppose that 62 percent of the graduates from your high school go on to four-year colleges, 15 percent go on to two-year college

inn [45]

Answer:

b) .474

Step-by-step explanation:

If 62% go to a four-year college, that means that those who don't represent 38% of the high-school graduates.

You pick up someone who is NOT going to a four-year college (so, he's among the 38%)... what's the chance he's in the 18% of the whole high-school graduates population that found a job?

To calculate that probability, we have to divide 18% by 38%.

P = 18% / 38% = 0.4736, so 0.474

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3 years ago

Find the area of trapezoid JKLM. Round the answer to the nearest tenth.

maksim [4K]

from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.

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2 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

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$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

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gladu [14]

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3 years ago

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