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Sladkaya [172]
3 years ago
12

Your bank account is sitting on $14,000. You started with a principal balance of $12,500. If the interest rate was 4.5% compound

ed continuously, how long was your money in the bank?
Mathematics
1 answer:
Simora [160]3 years ago
3 0

Answer:

t=2.5\ years  

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

t=?\ years\\ P=\$12,500\\P=\$14,000\\ r=4.5\%=4.5/100=0.045  

substitute in the formula above   and solve for t

14,000=12,500(e)^{0.045t}  

Simplify

14,000/12,500=(e)^{0.045t}  

1.12=(e)^{0.045t}  

Apply ln both sides

ln(1.12)=ln[(e)^{0.045t}]  

ln(1.12)=(0.045t)ln(e)  

Remember that

ln(e)=1  

so

ln(1.12)=(0.045t)  

t=ln(1.12)/(0.045)  

t=2.5\ years  

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5 0
2 years ago
Please help me
Nata [24]

Answer:

1 1/2

Step-by-step explanation:

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The LCD here is 6.  Convert 2 2/3 so that the denominator is 6:

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5 0
3 years ago
1/4d=1/5g(g+e)-h <br> solve for d<br> Please show your work.
loris [4]

Answer:

See below

Step-by-step explanation:

To solve for d, multiply both sides of the equal sign by 4.

4(1/4d) = 4 (1/5g(g+e)-h)

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d = 4/5g^{2} + 4/5ge - 4h

5 0
2 years ago
Actual lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy leng
HACTEHA [7]

Solution :

The data is normally distributed.

The standard deviation is 18 days

Here the data is normally distributed and 54 days is 3 days of standard deviation.

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= P( -3 < Z < 3)

= 0.9544

= 95 %

Therefore, about 95% of the births would be \text{expected to occur} within 54 days of the men \text{pregnancy} length.

8 0
2 years ago
How many distinct pairs of perfect squares differ by 35? (the pair $a, b$ is the same as the pair $b, a$.)?
Phantasy [73]
35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35

One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
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5 0
3 years ago
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