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3 years ago

2. Daniel orders sushi from the sushi restaurant. The total bill is $80. He tips the sushi chef 20%.

Mathematics

2 answers:

Neporo4naja [7]3 years ago

5 0

Answer:

Step-by-step explanation:

(20/100) * 80=16

kkurt [141]3 years ago

3 0

Answer:

Step-by-step explanation:

$20.43 is how much tip was

27% >>> .27

.27 * 75.68 = 20.43 tip

Bonus: $96.11

the bold word are tip but your answer is 16

mark me brinilylist

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(HELP) What is the domain and range of this parabola?

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Answer:

D: [0,8]

R: [0,3]

Step-by-step explanation:

The domain is the x-values covered by the graph, while the range is the y-values. So to find each, find the lowest and highest x and y value; since this graph is continuous the domain and range will include all values between these points. In this case, the lowest x is 0 and the highest is 8; the lowest y is 0 and the highest is 3. Then to write the answer write is from least to greatest, finally, surround the point by a parenthesis or bracket. The difference is that parenthesis means the value is not included while a bracket means it is. On this graph all points are included, therefore brackets should be used.

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3 years ago

PEASE HELP ASAP!!! The sum of two numbers is 58.

agasfer [191]

Answer:

y=15

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(any variable can be used, I used x and y to make it easier to show)

Step-by-step explanation:

x+y=58

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x=58-y

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Snezhnost [94]

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You want to find

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Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
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3 years ago