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fiasKO [112]
3 years ago
12

What is the value of y in the equation 5x + 2y =

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

Not Enough Details

Step-by-step explanation:

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If P(A)=0.4, P(A and B)=0.2,and P(A or B)=0.5, What is P(B)
Vladimir [108]

Answer:

\boxed{\ P(B)=0.3 \ }

Step-by-step explanation:

Hi,

We know that

P(A or B)=P(A)+P(B)-P(A and B)

so P(B)= P(A or B) - P(A) + P(A and B)

so

P(B) = 0.5 - 0.4 + 0.2 = 0.3

thanks

6 0
3 years ago
Please solve these hjgh
Kruka [31]

Answer:

  1. BDA
  2. ACD
  3. QBO

Step-by-step explanation:

BRO,HOW TO UPLOAD PDG

7 0
3 years ago
Translate f(x)= |x| so that it's translated up by 5 units and vertically stretched by a
natta225 [31]
B because I’ve done this before
4 0
2 years ago
What the answer to this question
Sonja [21]

To solve this, you need to isolate/get the variable "u" by itself in the inequality:            u = unknown number

2u - 3 < 1       Add 3 on both sides

2u - 3 + 3 < 1 + 3

2u < 4        Divide 2 on both sides to get "u" by itself

u < 2       (u is any number less than 2)

When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.

When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.

u < 2        

Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.

3 0
3 years ago
Find an equation for the graph
Elanso [62]

Answer:

y=6^x+0.612 - 4

Step-by-step explanation:

x = -4 ---> horizontal asymptote

m = 6 ---> use points (0, -1) and (1, 5)

Parent function of the graph: y=b^x

Our equation: y=6^x

Add alterations:

  1. Reflections = N/A
  2. Vertical & horizontal shifts = down 4
  3. Vertical & horizontal stretches = left approx 0.612

Final equation: y=6^x+0.612 - 4


6 0
2 years ago
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