Answer:
domain: {x | x is a real number}
range: {y l y> -8}
Step-by-step explanation:
f(x) = 4x² – 8 is a parabola, a U shape.
Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.
y > -8 because the minimum is -8.
Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.
Quadratic standard form:
f(x) = ax² + bx + c
"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.
"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.
"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.
y= -947/8
Just isolate the variables, even though this is a long, painstaking, agonizing process
:)
Answer:
convert 2/5 to a decimal, which is 0.4
multiplying a value by 10 means you should move the decimal point one unit to the right
so 10 x 2/5 = 4
Step-by-step explanation:
Answer:
Alternate interior angles
Step-by-step explanation:
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