All categories

3 years ago

(x+2) (y-5)=0 please help me graph and solve this!!

Mathematics

1 answer:

viktelen [127]3 years ago

4 0

(X+2)(y-5)=0

X+2=0
X=-2

Y-5=0
Y=5

X is horizontal
Y is vertical

You might be interested in

Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due

ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

Formula : d=v*t

at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

Formula : D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$

⇒ $D = \sqrt{20^2t^2+15(t-1)^2}$

Now let $F(t) = D^2(t)$

∵ $F'(t) = 800t + 450(t-1) = 1250t -450\\F'(t) =0$

⇒ t= 450/1250

⇒ t= .36 hours

⇒ = 21 min 36 sec

Since F"(t)=0,

∴ This time gives us a minimum.

Thus, The two boats will closet together at 2:21:36 pm.

3 0

3 years ago

NEED HELP NOW!!!

Amiraneli [1.4K]

D.

Explanation:

a landscape of farmland bisected by long straight roads"

divide into two parts.

hope I help you ☺️❤️

:) :>

8 0

2 years ago

A teacher is choosing 4 students from a class of 30 to represent the class at a science fair. In how many ways can the teacher c

marin [14]

${30 \choose 4}=\frac{30!}{4!26!}=\frac{27\cdot28\cdot29\cdot30}{2\cdot 3\cdot4}=27\cdot7\cdot29\cdot5=27405$

4 0

3 years ago

Please help!!!!! I'll give brainliest

7nadin3 [17]

Answer:

The ranger will need to clear trail for more than 10 2/3 additional hours.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Part A

olasank [31]

<h3>Answer:</h3>

B. f(x) = 3,000(0.85)^x
$1566.02

<h3>Step-by-step explanation:</h3>

Part A

At the end of the year, the value of the computer system is ...

... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)

... = 0.85 · (beginning value)

Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...

... f(x) = (beginning value) · 0.85^x

The beginning value is given as $3000, so this is ...

... f(x) = 3000·0.85^x

____

Part B

For x=4, this is ...

... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02

The value after 4 years is $1566.02.

8 0

3 years ago