Question

help plz really need your help if u know answer if u don't DO NOT ANSWER this is not the first time I have posted this question​

Answer 1

T eg(1) : 97.5°C, T eg(2): 98.5°C, T eg(3): 99.2°C

∆T water(1): -2.5°C, ∆T water(2): -1.5°C, ∆T water(3): -0.8°C

∆T metal(1): 77.5°C, ∆T metal(2): 80.5°C, ∆T metal(3): 80.2°C.

ft= (m1 cp1 t1 + m2 cp2 t2 + .... + mn cpn tn) / (m1 cp1 + m2 cp2 + .... + mn cpn) (1)

where,

1000g = 1kg

ft(t eg)= final mixed temperature (°C)

m = mass of substance (kg)

cp = specific heat of substance (J/kg°C)

t = temperature of substance (°C)