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Vedmedyk [2.9K]
3 years ago
13

The predominant intermolecular force in (ch3)2nh is ________. the predominant intermolecular force in (ch3)2nh is ________. lond

on dispersion forces ion-dipole forces hydrogen bonding ionic bonding dipole-dipole forces
Chemistry
1 answer:
zalisa [80]3 years ago
3 0
The predominant intermolecular force in (CH3)2NH is <span>hydrogen bonding.
</span>Hydrogen bond<span> is an </span>electrostatic<span> attraction between two polar groups in which one group has hydrogen atom (H) and another group has highly electronegative atom such as nitrogen (like in this molecule), oxygen (O) or fluorine (F).</span>
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a photon of light has a frequency of 3.5 x 10 to the 14th Hertz what is the wavelength of this light what color is this late
Oliga [24]

Wavelength relates to frequency as follows: λ=vf in which f is the frequency, v is the speed of light, and λ is the wavelength.

4 0
3 years ago
View Available Hint(s) Check all that apply. Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an NN, OO, or
Sauron [17]

Answer:

Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an NN, OO, or FF atom.

A hydrogen atom acquires a partial positive charge when it is covalently bonded to an FF atom.

A hydrogen bond is possible with only certain hydrogen-containing compounds.

Explanation:

A hydrogen bond does not occur in all hydrogen containing compounds. Hydrogen bonds only occur in those compounds where hydrogen is bonded to a highly electronegative element such as fluorine, oxygen or nitrogen.

In a hydrogen bonded specie, hydrogen acquires a partial positive charge and the electronegative element acquires a partial negative charge which extends throughout the molecule.

7 0
3 years ago
Using the following equation: 3H2SO4+ 2Fe -&gt; Fe2(SO4)3+ 3H2
Mariana [72]

Answer:

H₂SO₄

Explanation:

Given data:

Number of moles of H₂SO₄ = 15 mol

Number of moles of Fe = 13 mol

Which reactant is limiting reactant = ?

Solution:

Chemical equation:

3H₂SO₄  + 2Fe      →          Fe₂(SO₄)₃  + 3H₂

now we will compare the moles reactant with product.

               H₂SO₄         :          Fe₂(SO₄)₃  

                  3               :              1

                 15               :              1/3×15 = 5

                H₂SO₄         :            H₂

                  3               :              3

                 15               :              15

                Fe               :          Fe₂(SO₄)₃  

                  2               :              1

                 13               :              1/2×13 = 6.5

                Fe               :                H₂

                  2               :                 3

                 13               :              3/2×13 = 19.5

Number of moles of product formed by  H₂SO₄ are less thus it will act as limiting reactant.

8 0
3 years ago
The standard free energy of activation of one reaction A is 95.00 kJ mol–1 (22.71 kcal mol–1). The standard free energy of activ
diamong [38]

Answer:

The answer to the questions are as follows

Reaction B is 4426.28 times faster than reaction A

(b) Reaction B is faster.

Explanation:

To solve the question we are meant to compare both reactions to see which one is faster

The values of the given activation energies are as follows

For A

Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and

for  B

Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

The Arrhenius Law is given by

k = Ae^{\frac{-E_{a} }{RT} }

Where

k = rate constant

Ea = activation energy

R = universal gas constant

T = temperature  (Kelvin )

A = Arrhenius factor

Therefore

For reaction A, the rate constant k₁ is given by k₁ = Ae^{\frac{-95000}{(8.314)(298)} }

And for B the rate constant k₂ is given by k₂ = Ae^{\frac{-74200 }{(8.314)(298)} }

k₁ = A×2.225×10⁻¹⁷

k₂ = A×9.850×10⁻¹⁴

As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times

3 0
3 years ago
How many molecules are there in 5.0g of C2H5OH?
Vilka [71]
About 6.5x10^22 molecules. (5g C2H5OH)x(1 mol C2H5OH/46g C2H5OH)x(6.02x10^23 molecules C2H5OH/1 mol C2H5OH)=(3.01E24)/46=6.5x10^22. Let me know if this helped!
4 0
3 years ago
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