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shtirl [24]
3 years ago
6

65.5g of copper reacts with __g of oxygen to produce 81g copper(I) oxide

Chemistry
1 answer:
Nikitich [7]3 years ago
7 0

Answer:

grams O₂(g) ≅ 15.9 g O₂(g) (3 sig. figs.)  

Explanation:

2Cu + O₂ => 2CuO

Convert given to moles, solve by equation rxn ratio then convert to grams.

Moles CuO formed = 81.0 g / 81.5 g·mol⁻¹ = 0.994 mol CuO

0.994 mol CuO requires 0.994 mol Cu = 0.994 mol Cu x 64 g·mol⁻¹ = 63.6 g Cu => from this, the amount of O₂ needed = 1/2(0.994 mol) O₂(g) = 0.497 mol O₂(g) = (0.497 mol O₂(g))(32 g·mol⁻¹) = 15.904 g O₂(g) ≅ 15.9 g O₂(g) (3 sig. figs.)                

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A gas occupies a volume of 140 ml at 30 degrees Celsius and 97 Kpa. What is the volume of the gas at stp
lara31 [8.8K]
The standard temperature and the pressure for a gas are 273 K and 1 atm (1.0 x 10⁵ Pa) respectively.

For this question, combined gas law can be added.

PV/T = K (constant)

for both situations that law can be added as;
P₁V₁/T₁ = P₂V₂/T₂

P₁ = 97 kPa                           P₂= 1.0 x 10⁵ Pa
T₁ = 303 K                             T₂ = 273 K
V₁ 140 mL                              V₂ = ?

V₂ = 122.3 mL

Hence, the volume of gas at STP = 122.3 mL


5 0
3 years ago
Please include an explanation
Vesna [10]

Answer:

The explanation to your question is below.

Explanation:

In thermochemistry, reactions are classify in two groups.

- Endothermic reactions: are reactions that need energy (heat) from the surroundings to happen. If they are not heated, the products will not form.

Example:

                        2 H₂O + energy ⇒ 2H₂  + O₂

-Exothermic reactions: are reactions that release energy to the surroundings. They happen spontaneously.

Example:

                       CH₄  + 2O₂   ⇒   CO₂   +  2H₂O + energy (heat)

4 0
3 years ago
What happens when sugar disolves in water?
Elis [28]

First, the sugar dissolves into small sugar molecules, Then fills in the spaces in between the water molecules thus, making Sugar water.

I hope that answered your question and has come to your help.

4 0
4 years ago
Read 2 more answers
If 40.0 g of molten iron(II) oxide reacts with 10.0 g of mag-nesium, what is the mass of iron produced
vagabundo [1.1K]

Answer:

m_{Fe}=23.0gFe

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

FeO+Mg\rightarrow Fe+MgO

Thus, for the given masses of reactants we should compute the limiting reactant for which we first compute the available moles of iron (II) oxide:

n_{FeO}=40.0gFeO*\frac{1molFeO}{72gFeO} =0.556molFeO

Next, we compute the consumed moles of iron (II) oxide by the 10.0 g of magnesium, considering their 1:1 molar ratio in the chemical reaction:

n_{FeO}^{consumed}=10.0Mg*\frac{1molMg}{24.3gMg}*\frac{1molFeO}{1molMg}=0.412molFeO

Therefore, we can notice there is less consumed iron (II) oxide than available for which it is in excess whereas magnesium is the limiting reactant. In such a way, the produced mass of iron turns out:

m_{Fe}=0.412molFeO*\frac{1molFe}{1molFeO}*\frac{56gFe}{1molFe}\\  \\m_{Fe}=23.0gFe

Regards.

8 0
4 years ago
A machine has a mechanical advantage of 0.6. What force should be applied to the machine to make it apply 600 N to an object?
Vinil7 [7]

Answer:

1000N is needed to be applied.

Explanation:

Machines make doing work easier. They allow us use small effort to carry out work on huge amount of load.

The mechanical advantage of a machine;

(M.A) =load/effort

M.A = 0.6

Load =600N

effort =?

0.6 = 600/effort

effort = 600/0.6

effort = 1000N

8 0
3 years ago
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