Answer:
that's the area of a circle
its πr²1
Answer:
✓✓ Area of traingle = 1.2 cm^2 ✓✓
Step-by-step explanation:
Hello mate (◕ᴗ◕✿)
=>> In above traingle, <u>height and hypotenuse are </u><u>given</u>
<u>=</u><u>></u><u> </u><u>height</u><u> </u>= 12 cm
<u>=</u><u>></u><u> </u><u>Hypotenuse</u> = 14 cm
✓✓ <u>Area</u><u> of</u><u> </u><u>traingle </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>base*</u><u>height</u><u>)</u><u> </u><u>✓</u><u>✓</u>
<u> </u>we need to find base of above traingle
<u>Base </u><u>=</u><u> </u><u>√</u><u>H</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u> </u><u>-</u><u> </u><u>√</u><u>P</u><u>e</u><u>r</u><u>p</u><u>i</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u> </u>
Base = √14 - √12
Base = 3.7 - 3.4
Base = 0.2 cm
Now, we can find area of traingle
<u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>Base*</u><u>Height</u><u>)</u>
<u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>0</u><u>.</u><u>2</u><u>*</u><u>1</u><u>2</u><u>)</u>
<u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>6</u><u>*</u><u>0</u><u>.</u><u>2</u>
<u> </u><u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>.</u><u>2</u><u> </u><u>cm^</u><u>2</u>
<u> </u>Hope it helps you mate (. ❛ ᴗ ❛.)
We have to put values of domain to find range
Now
The answer is 12root3 which is 20.78 to 2dp.
Answer:
(-1,3)
Step-by-step explanation:
Given that the quadrilateral ABCD is translated to get quadrilateral A'B'C'D'. The vertex A is at (-5,2) is translated to vertex A' is at (2,-2).
The translation is x-direction, a, is the difference of x-coordinates of both the points, a=2-(-5)=2+5=7.
The translation is y-direction, b, is the difference of y-coordinates of both the points, b = -2-2 = -4.
As all the points are translated by the same magnitude as well as in the same direction, so by adding a to x and b to y coordinate of any points, the translated point can be determined.
The vertex of point B is (-6,5), so, the vertex of the point B' would be (-6+a, 5+b)=(-6+7, 5+(-4))=(-1,3).
Hence, the vertex of point B' is (-1,3).