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V125BC [204]
3 years ago
11

DOES ANYONE GET THIS? ):

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

There is a given point (10,3) this shows that when the width (X) is 10, the height (Y) is 3.

On the left side of the graph, they show an equation for the height Hw as being the constant over w ( width).

Using the given point solve for the constant.

Replace Hw with 3 and w with 10:

3 = Constant/10

Solve for the constant by multiplying both sides by 10:

Constant = 3 x 10

Constant = 30

The answer is B.

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All even prime numbers
KengaRu [80]

Answer:

2

Step-by-step explanation:

2 is the only even prime number.

5 0
3 years ago
Factor to find the zeros of the function defined by the quadratic expression. −7x2 − 91x − 280
Mariulka [41]
There are no zeroes for an expression, only for equations.
Assuming equation to be
<span>−7x^2 − 91x − 280=0
-7(x^2+13x+40)=0
-7(x+8)(x+5)=0
by the zero product properties, 
x+8=0 => x=-8
or 
x+5=0 => x=-5</span>
3 0
3 years ago
Please I need this ASAP so can someone helpppppp
iris [78.8K]
AC = 8.9
BC = 6.5
(90% angle)
8.9 x 6.5 = <span>57.85
57.85/2 = 28.925
Area of ^ABC =  28.925 cm squared

DE = 55.1
55.1/ 11.02 = 5
DEF is 5 times as big as ABC
DF = 44.5
FE = 32.5
44.5 x 32.5 = 1446.25
1446.25/2 = 723.125
I am not positive but I believe DEF = 723.125 cm squared
Good Luck on the Test!! :D

</span>
7 0
3 years ago
For problem 5, use the ordered pairs to answer the following question. MUST SHOW YOUR WORK FOR FINDING SLOPE.
Firlakuza [10]

Answer:

graph them and then see if they intersect(but if you notice that the coordss of the second line are all smaller than the coords of the first line, meaning that they wont be touching at all)

Step-by-step explanation:

7 0
3 years ago
Which choice is the equation of a line that passes through (9, -3) and is parallel to the line represented by this equation? y=5
miskamm [114]

Answer:

y+3=\frac{5}{3}(x-9)  or  y=\frac{5}{3}x-18

Step-by-step explanation:

step 1

Find the slope of the line parallel to the given line

we know that

If two lines are parallel, then their slopes are the same

we have

y=\frac{5}{3}x-4

therefore

The slope m of the line parallel to the given line is

m=\frac{5}{3}

step 2

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{5}{3}

point\ (9,-3)

substitute

y+3=\frac{5}{3}(x-9) ----> equation of the line in point slope form

step 3

Find the equation of the line in slope intercept form

y=mx+b

we have

y+3=\frac{5}{3}(x-9)

Isolate the variable y

y+3=\frac{5}{3}x-15

y=\frac{5}{3}x-15-3

y=\frac{5}{3}x-18

7 0
3 years ago
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