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3 years ago

−6x−3(x−2) PLEASE HELP

Mathematics

1 answer:

vodomira [7]3 years ago

5 0

Answer:

-9x + 6

Step-by-step explanation:

-6x−3(x−2)

Solution:

-6x−3(x−2)

-6x−3x+6

-9x + 6

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Answer:

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Step-by-step explanation:

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3 years ago

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ABC ≃DEF. Find the lengths of the given sides

GuDViN [60]

Answer:

BC = 8 and EF = 8.

Step-by-step explanation:

Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).

Set BC and EF equal to each other.

x + 6 = 3x + 2

Subtract x from both sides.

6 = 2x + 2

Subtract 2 from both sides.

4 = 2x.

Divide 2 on both sides.

x = 2.

Substitute 2 for x.

BC = 2 + 6

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Since we already know that EF is congruent to BC, EF is also 8.

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3 years ago

Find the volume of the figure. Round your answer to the nearest tenth if necessary. Use 3.14 for T.

seraphim [82]

Answer:

$\boxed{ \rm \: Volume_{(Cylinder)} \approx \: 461.6 \: {m}^{3} } \rm (rounded \: to \: nearest \: tenth)$

Step-by-step explanation:

Given dimensions:

Radius of the cylinder = 7 metres
Height of the cylinder = 3 metres

Given value of π :

π = 3.14

To find:

The Volume of the cylinder

Solution:

Here, we'll need to use the formulae of the volume of cylinder,to find it's volume.Its actually like a savior while solving these type of questions.

$\pink{\star}\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}\pink{\star}$

where,

π = 3.14
r² = (radius)²
h = height

Plug/substitute them onto the formulae,then simplify it using PEMDAS.

[We'll substitute the value of π later]

$\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2} \times 3$

$\rm \: Volume_{(Cylinder)} = \pi(49)(3)$

$\rm \: Volume_{(Cylinder)} = 147\pi \:$

Now substitute the value of π.

$\rm \: Volume_{(Cylinder)} = 147 \times 3.14$

$\rm \: Volume_{(Cylinder)} = 461.58 \: {m}^{3}$

$\boxed{\rm \: Volume_{(Cylinder)} \approx \: 461.6 \: {m}^{3}} \rm (rounded \: to \: nearest \: tenth) \:$

<u>Hence, we can conclude that:</u>

The volume of the cylinder is approximately

461.6 m³.

$\rule{225pt}{2pt}$

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