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MrMuchimi
3 years ago
5

−6x−3(x−2) PLEASE HELP

Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

-9x + 6

Step-by-step explanation:

-6x−3(x−2)

Solution:

-6x−3(x−2)

-6x−3x+6

-9x + 6

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Step-by-step explanation:

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ABC ≃DEF. Find the lengths of the given sides
GuDViN [60]

Answer:

BC = 8 and EF = 8.

Step-by-step explanation:

Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).

Set BC and EF equal to each other.

x + 6 = 3x + 2

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3 years ago
Find the volume of the figure. Round your answer to the nearest tenth if necessary. Use 3.14 for T.
seraphim [82]

Answer:

\boxed{ \rm \: Volume_{(Cylinder)} \approx \: 461.6  \:  {m}^{3} } \rm (rounded \: to \: nearest \: tenth)

Step-by-step explanation:

Given dimensions:

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Solution:

Here, we'll need to use the formulae of the volume of cylinder,to find it's volume.Its actually like a savior while solving these type of questions.

\pink{\star}\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}\pink{\star}

where,

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Plug/substitute them onto the formulae,then simplify it using PEMDAS.

  • [We'll substitute the value of π later]

\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2}  \times 3

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\rm \: Volume_{(Cylinder)} = 147\pi \:

  • Now substitute the value of π.

\rm \: Volume_{(Cylinder)} = 147 \times 3.14

\rm \: Volume_{(Cylinder)} = 461.58 \:  {m}^{3}

\boxed{\rm \: Volume_{(Cylinder)} \approx \: 461.6  \:  {m}^{3}} \rm (rounded \: to \: nearest \: tenth) \:

<u>Hence, we can conclude that:</u>

The volume of the cylinder is approximately

461.6 m³.

\rule{225pt}{2pt}

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