Answer:
area of circle having radius 3
is πr²=π*3²=9π square units
area of circle having radius 2
=πr²=π×2²=4π square units
again
area of big circle having radius [3+2]=5 units
=πr²=π×5²=25π square units
Now
area of shaded region=25π-4π-9π=12π or 37.7square units.
Answer:
the correct answer would be option 4, since both triangle ACD and triangle ECB
Common factors for the various terms include -1, 7, y. Factoring out the product of those gives ...
... -7y(3xz +4x +5z) . . . . . . matches selection B)
Answer: 31 and 1/9
Step-by-step explanation:
d =29, for g=16,h=9
replace values of each number in equati/on:
d+g/h=29+19/9=(9*29+19)/9=( 261+19)/9=280/9= 31 and 1/9
Answer:
x=2,6
Step-by-step explanation:
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.