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3 years ago

Which net represents the figure. Plz help meeeeeeeee

Mathematics

2 answers:

nikdorinn [45]3 years ago

8 0

Answer:

bottom left corner

Step-by-step explanation:

Goshia [24]3 years ago

3 0

The fourth graph or D (the one in the bottom right corner) this is because a pyramid consists of four triangles and one square at the bottom.

Correct me if wrong
Have a nice day :D
~Hackermcpe

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Multiply: 5x(2x4 – x3 + 3)

Leno4ka [110]

Answer:

−

Step-by-step explanation:

6 0

3 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

Is 40 is 50% of 80 true or false<br> With step by step evidence

Fantom [35]

Answer:

please mark brainliest

it is true

Step-by-step explanation:

if you multiplie 80 by 0.50 you will get 40,

4 0

2 years ago

17X+1 +20x-14 = 90<br> find x

professor190 [17]

Answer:

x = 2.8

Step-by-step explanation:

17x+1+20x-14 = 90

Combine like terms.

37x-13 = 90

Add 13 on both sides.

37x-13 = 90

37x = 103

Divide both sides by 37.

37x = 103

x = 2.8

(I rounded up, but if you need a more specific number, just search up 103 divided by 37.)

Hopefully this helps you!! Have an amazing day c:

7 0

3 years ago

Which point below is a solution to the equation y = 2x + 3?

Anastasy [175]

Answer:

C (37, 77)

Step-by-step explanation:

<h3>Option A:</h3>

$291=2(145)+3\\\\291=290+3\\\\\boxed{291\neq 293}$

Option A is not a solution.

<h3>Option B:</h3>

$163=2(78)+3\\\\163=156+3\\\\\boxed{163\neq 159}$

Option B is not a solution.

<h3>Option C:</h3>

$77=2(37)+3\\\\77=74+3\\\\\boxed{77=77}$

Option C is a solution.

Hope this helps.

6 0

3 years ago

Read 2 more answers