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Crank
2 years ago
15

If anyone can help, it’d be appreciated! I’m so confused

Mathematics
1 answer:
irga5000 [103]2 years ago
4 0
I think it’s the first option
Sorry if it’s wrong
Hope that helped
I’m bo red so I’m helping out
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A probability experiment is conducted in which the sample space of the experiment is upper s equals { 1 comma 2 comma 3 comma 4
Softa [21]

You can think of this experiment as follows: you have to select a random number between 1 and 15, where each number is equally likely to appear.

Player A wins if 3,4,5 or 6 are picked.

Player B wind is 10,11 or 12 are picked.

Two events are said to be mutually​ exclusive if they cannot happen at the same time. So, in our metaphor, the question is: can we pick a particular number, so that both players win simultaneously?

The question is no, because if player A wins, we have picked 3,4,5 or 6, and player B wins with none of these numbers.

Similarly, if player B wins, we have picked 10, 11 or 12, and player A wins with none of these numbers.

So, the two events cannot occur simultaneously.

If you want to be more formal, since the events are subset of the sample space, two events are mutually exclusive if their intersection is the empty set, and this is the case:

A \cap B = \{3,4,5,6\}\cap\{10,11,12\} = \emptyset

8 0
3 years ago
What is the lateral area of the cylinder?
Sunny_sXe [5.5K]
   
<span>D = 22ft
h = 9 ft

Lateral area of the cylinder = </span>π × D × h = 3,14 × 22 × 9 = 621,72 ft²



3 0
2 years ago
Read 2 more answers
Determine whether the ordered pair is a solution of the linear inequality
katrin2010 [14]

Step-by-step explanation:

So you solve the equation for x and then solve it for y. If the x and y match the given ordered pair then the answer is yes

3 0
2 years ago
The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th
timama [110]

Answer: (0.076, 0.140)

Step-by-step explanation:

Confidence interval for population proportion (p) is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} = sample proportion.

n= sample size.

\alpha = significance level .

z_{\alpha/2} = critical z-value (Two tailed)

As per given , we have

sample size : n= 500

The number of Independents.:  x= 54

Sample proportion of Independents\hat{p}=\dfrac{x}{n}=\dfrac{54}{500}=0.108

Significance level 98% confidence level : \alpha=1-0.98=0.02

By using z-table , Critical value : z_{\alpha/2}=z_{0.01}=2.33

The 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters will be :-

0.108\pm (2.33)\sqrt{\dfrac{0.108(1-0.108)}{500}}\\\\=0.108\pm2.33\times0.013880634\\\\=0.108\pm0.03234187722\\\\\approx0.108\pm0.032=(0.108-0.032,\ 0.108+0.032)=(0.076,\ 0.140)

Hence, the 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters.= (0.076, 0.140)

8 0
3 years ago
Kiersten runs a website that helps people learn programming. Every month, Kiersten receives a subscription fee of \$10$10dollar
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