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elixir [45]
3 years ago
13

Why can an increase in temperature lead to more effective collisions between reactant particles and an increase in the rate of a

chemical reaction?
(1) The activation energy of the reaction increases.
(2) The activation energy of the reaction decreases.
(3) The number of molecules with sufficient energy to react increases.
(4) The number of molecules with sufficient energy to react decreases.
Chemistry
2 answers:
stellarik [79]3 years ago
5 0

Answer: Option (c) is the correct answer.

Explanation:

Activation energy is the minimum amount of energy required by the reactant molecules to undergo a chemical reaction.

Therefore, when temperature is increased then there will be increase in number of collisions between the reactant molecules. Hence, molecules with lesser energy than the activation energy will also gain energy and thus, they will effectively participate in the chemical reaction.

Hence, we can conclude that an increase in temperature lead to more effective collisions between reactant particles and an increase in the rate of a chemical reaction because the number of molecules with sufficient energy to react increases.

ankoles [38]3 years ago
3 0

An an increase in temperature lead to more effective collisions between reactant particles and an increase in the rate of a chemical reaction because the number of molecules with sufficient energy to react increases. The answer is number 3.

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How many molecules are there in 560 grams of CoCl2?​
Marrrta [24]

Answer:

25.89  × 10²³ molecules

Explanation:

Given data:

Mass of CoCl₂ = 560 g

Number of molecules present = ?

Solution:

Number of moles of CoCl₂:

Number of moles = mass/molar mass

Number of moles = 560 g/ 129.84 g/mol

Number of moles = 4.3 mol

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

4.3 mol ×  6.022 × 10²³ molecules /1 mol

25.89  × 10²³ molecules

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2 years ago
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Acetylene burns in air according to the following equation: C2H2(g) + 5 2 O2(g) → 2 CO2(g) + H2O(g) ΔH o rxn = −1255.8 kJ Given
professor190 [17]

Answer:  -227 kJ

Explanation:

The balanced chemical reaction is,

C_2H_2(g)+\frac{5}{2}O_2(g)\rightarrow 2CO_2(g)+H_2O(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+ n_{H_2O}\times \Delta H_{H_2O})]-[(n_{C_2H_2}\times \Delta H_{C_2H_2})+(n_{O_2}\times \Delta H_{O_2})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-1255.8=[(2\times -393.5)+(1\times -241.8)]-[(1\times \Delta H_{C_2H_2})+(\frac{5}{2}\times 0)]

-1255.8=[(-787)+(-241.8)]-[(1\times \Delta H_{C_2H_2})+(0)]

\Delta H_{C_2H_2}=-227kJ

Therefore, the enthalpy change for C_2H_2 is -227 kJ.

7 0
3 years ago
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