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Burka [1]
3 years ago
12

For the reaction, calculate how many grams of the product form when 14.4 g of Br2 completely reacts. Assume that there is more t

han enough of the other reactant. 2K(s)+Br2(l)→2KBr(s)
Chemistry
1 answer:
lora16 [44]3 years ago
7 0

Answer:

The answer to your question is 21.45 g of KBr

Explanation:

Chemical reaction

                               2K + Br₂   ⇒   2KBr

                                       14.4            ?

Process

1.- Calculate the molecular mass of bromine and potassium bromide

Bromine = 2 x 79.9 = 159.8g

Potassium bromide = 2(79.9 + 39.1) = 238 g

2.- Solve it using proportions

              159.8 g of Bromine ------------ 238 g of potassium bromide                    

                14.4 g of Bromine  ------------  x

                        x = (14.4 x 238) / 159.8

                        x = 3427.2 / 159.8

                        x = 21.45g of KBr

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Given one mole of each substance, which of the following will produce the FEWEST particles in aqueous solution? 1. sodium nitrat
svlad2 [7]

<u>Answer:</u> The substance that produces fewest particles is CH_2Cl_2

<u>Explanation:</u>

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

Covalent compounds do not dissociate into ions when dissolved in aqueous solution.

For the given options:

  • <u>Option 1:</u>  Sodium nitrate

The chemical formula of sodium nitrate is NaNO_3

The ionization reaction for the given compound follows:

NaNO_3(aq.)\rightarrow Na^+(aq.)+NO_3^-(aq.)

This produces in total of 2 ions.

  • <u>Option 2:</u>  CH_2Cl_2

The given compound is a covalent compound and do not dissociate into its ions. It remains as such as a single unit.

  • <u>Option 3:</u>  K_2SO_4

The chemical name for the given compound is potassium sulfate.

The ionization reaction for the given compound follows:

K_2SO_4(aq.)\rightarrow 2K^+(aq.)+SO_4^{2-}(aq.)

This produces in total of 3 ions.

  • <u>Option 4:</u>  Sodium phosphate

The chemical formula of sodium phosphate is Na_3PO_4

The ionization reaction for the given compound follows:

Na_3PO_4(aq.)\rightarrow 3Na^+(aq.)+PO_4^{3-}(aq.)

This produces in total of 4 ions.

Hence, the substance that produces fewest particles is CH_2Cl_2

3 0
3 years ago
If an atom has 22 protons 28 neutrons 20 electrons what would its atomic number be
AURORKA [14]

Answer:

22

Explanation:

The atomic number indicates the amount of protons, so it would be 22

4 0
3 years ago
How do ionization energies provide evidence for the quantization of the energies of electrons?
lina2011 [118]
The electrons are electrically charged
7 0
3 years ago
A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner.
irakobra [83]
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
     Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo

We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
     Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g 

We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
     Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O

To convert mass to moles, we use the molar mass of each element.
     1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
     0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O

0.0131 mol is the smallest number of moles. We divide each mole value by this number:
     0.0131 mol Mo / 0.0131 = 1
     0.0200 mol O / 0.0131 = 1.53

Multiplying these results by 2 to get the lowest whole number ratio,
     0.0131 mol Mo / 0.0131 = 1 * 2 = 2
     0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
5 0
3 years ago
Read 2 more answers
NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te
makvit [3.9K]

Answer:

There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

Explanation:

To decrease the temperature of the solution there are necessaries:

4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y

8368J + 83,68J/gX = Y <em>(1)</em>

Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.

Also, the energy Y will be:

Y = 25700J/mol×\frac{1mol}{80,043g}X

Y = 321J/g X <em>(2)</em>

Replacing (2) in (1)

8368J + 83,68J/g X = 321J/g X

8363J = 237,32J/gX

<em>X = 35,2g</em>

<em />

Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

I hope it helps!

6 0
3 years ago
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