The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
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the specific heat capacity of the metal is 0.45 J/g⁰C.
The given parameters;
- <em>mass of water, </em>
<em> = 45 g</em> - <em>final temperature of the water, </em>
<em> = 22 ⁰C</em> - <em>mass of the metal, m = 8.5 g</em>
- <em>initial temperature of the metal, t = 82 ⁰C.</em>
- <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>
The initial temperature of the water will be calculated by applying the principle of conservation of energy;
<em>heat gained by water = heat lost by metal</em>
where;
<em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>
<em />
<em>Substitute the given values;</em>
45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)
4142.16 - 188.28t = 240.98
188.28t = 4142.16 - 240.98
188.28t = 3901.18
Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
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Answer:
Magnesium bromide, MgBr2, and water, H2O.
Explanation:
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In this case, since HBr is an acid and Mg(OH)2 is a base, an acid-base reaction is undergone, by which a salt and water are produced as neutralization products:
However, it need to be balanced since two bromine atoms are produced, therefore we write:
Thus, the products are magnesium bromide, MgBr2, and water, H2O.
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Answer:
The mechanism is in the attached file. The reaction intermediates are the following: C4H8O, C4H9O
Explanation:
Terbutanol is a tertiary alcohol. It is one of the four isomers of butanol. It is a transparent liquid (or a colorless solid, depending on the temperature), with an odor similar to camphor. It is very soluble in water and ethanol.
The scheme shows a protonation of the double bond and the nucleophilic attack of the water to the carbocation, then it loses a proton and the terbutanol is formed.
Answer: A. A bond in which molecules share electrons
