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3 years ago

Identify two ways that temperature plays a role in chemical changes.

Chemistry

1 answer:

sergejj [24]3 years ago

3 0

Answer:

Increasing the temperature will cause chemical changes to occur faster. Decreasing the temperature, causes the particles to lose energy which causes them to move around less and slower. The less they move, the less collisions occur, and the less reactions occur between the chemicals = slower reaction rate.

Explanation:

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PLEASE HELP OR EXPLAIN!!

Naddik [55]

The third one beacuse if you count all the atoms of every one you will find that one the left side, you have 3 h and on the right you have 2 h

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3 years ago

An atom's configuration based on its number of electrons ends at 3p3. Another atom has nine more electrons. Starting at 3p, what

77julia77 [94]

<h3><u>Answer;</u></h3>

3p34s23d7

<h3><u>Explanation</u>;</h3>

Electrons in an atom are contained in specific energy levels that are different distances from the nucleus.
Within each energy level is a volume of space where specific electrons are likely to be located, called orbitals. Orbitals are of different shapes, denoted by a letter (s, p, d, f, g).
S-orbital takes a maximum of two electrons, p-orbital take a maximum of six electrons, d-orbital takes a maximum of 10 electrons, and so fourth.
The electron filling pattern takes; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p.........
Therefore; in this case after 3p3, we then go to 4s, with 2 electrons, then 3d which takes 7 electrons.

8 0

2 years ago

Read 2 more answers

50cm3 of 1 mol/dm3 HCl at 30°C was mixed with 50cm3 of 1mol/dm3 NaOH at 30°C in a styrofoam calorimeter. The temperature of the

trapecia [35]

Answer:

-21 kJ·mol⁻¹

Explanation:

Data:

H₃O⁺ + OH⁻ ⟶ 2H₂O

V/mL: 50 50

c/mol·dm⁻³: 1.0 1.0

ΔT = 4.5 °C

C = 4.184 J·°C⁻¹g⁻¹

C_cal = 50 J·°C⁻¹

Calculations:

(a) Moles of acid

$\text{Moles of acid} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}\\\\\text{Moles of base} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}$

So, we have 0.050 mol of reaction

(b) Volume of solution

V = 50 dm³ + 50 dm³ = 100 dm³

(c) Mass of solution

$\text{Mass of solution} = \text{100 dm}^{3} \times \dfrac{\text{1.00 g}}{\text{1 dm}^{3}} = \text{100 g}$

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

nΔH + mCΔT + C_calΔT = 0

0.050ΔH + 100×4.184×4.5 + 50×4.5 = 0

0.050ΔH + 1883 + 225 = 0

0.050ΔH + 2108 = 0

0.050ΔH = -2108

ΔH = -2108/0.0500

= -42 000 J/mol

= -42 kJ/mol

This is the heat of reaction for the formation of 2 mol of water

The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.

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2 years ago

What type of waves are sound waves?

luda_lava [24]

Heya!!!

Answer to your question:

D)transverse

Sound waves are transverse waves.

Hope it helps ^_^

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3 years ago

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Which objects cannot be observed in detail without a microscope?

Sonbull [250]

The objects which cannot be observed in detail without a microscope

include the following:

Red blood cell

Bacterium

<h3>What is a Microscope?</h3>

A microscope is an instrument which is used to view smaller objects such as

microbe,cells, tissues etc. This instrument is used in viewing the different

cells found in the body as they can't be seen with the eye.

The remaining options which can be seen with the eyes don't require

the use of microscopes.

Read more about Microscope here brainly.com/question/25268499

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1 year ago