A 300.0-kg speedboat is moving across a lake at 35.0 m/s.
2 answers:
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Corrected question: The wavelength of light beam<u> </u><u>A</u> is twice the wavelength of light beam B. The energy of a photon in beam A is:
Answer:
B
Explanation:
Energy = hc/λ
λ(A) =2λ(B)...................equation 1
We will solve for the ratio of energy of A to energy of B.which is
=(hc/λA) ÷ (hc/λB)
referring to equation 1 we have
=(hc/2λB) ÷ (hc/λB)
=hc/2λB) × (λB/hc)
= λB/2λB
=1/2
The energy of A is half of B
Answer:
The velocity of the merry-go-round after the boy hops on the merry-go-round is 1.5 m/s
Explanation:
The rotational inertia of the merry-go-round = 600 kg·m²
The radius of the merry-go-round = 3.0 m
The mass of the boy = 20 kg
The speed with which the boy approaches the merry-go-round = 5.0 m/s
Where;
= The tangential force
I = The rotational inertia
m = The mass
α = The angular acceleration
r = The radius of the merry-go-round
For the merry go round, we have;
= The rotational inertia of the merry-go-round
= The angular acceleration of the merry-go-round
= The linear velocity of the merry-go-round
t = The time of motion
For the boy, we have;
Where;
= The rotational inertia of the boy
= The angular acceleration of the boy
= The linear velocity of the boy
t = The time of motion
When the boy jumps on the merry-go-round, we have;
Which gives;
From which we have;
The velocity of the merry-go-round, , after the boy hops on the merry-go-round = 1.5 m/s.