We have the equation:
We know two points and we will use them to calculate the parameters a and b.
The point (0,3) will let us know a, as b^0=1.
Now, we use the point (2, 108/25) to calcualte b:
![\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%3D3%5Ccdot%20b%5Ex%20%5C%5C%20%5Cfrac%7B108%7D%7B25%7D%3D3%5Ccdot%20b%5E2%20%5C%5C%203%5Ccdot%20b%5E2%3D%5Cfrac%7B108%7D%7B25%7D%20%5C%5C%20b%5E2%3D%5Cfrac%7B108%7D%7B25%5Ccdot3%7D%3D%5Cfrac%7B108%7D%7B3%7D%5Ccdot%5Cfrac%7B1%7D%7B25%7D%3D%5Cfrac%7B36%7D%7B25%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B%5Cfrac%7B36%7D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B%5Csqrt%5B%5D%7B36%7D%7D%7B%5Csqrt%5B%5D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B6%7D%7B5%7D%20%5Cend%7Bgathered%7D)
Then, we can write the equation as:
Answer:
x=61
Step-by-step explanation:
I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Answer:
Pure imaginary
Step-by-step explanation:
Supplementary means they equal 180 when added. Therefore:
X+56+3x=180
Combine common units
4x+56=180
Subtract 56 from both sides
4x=124
Divide by 4
X=31
Now we know the smaller angle is 31 degrees. Now we plug that into the larger angle:
3(31)+56
93+56
149
The larger angle is 149 degrees.
I hope this Helps!
