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Westkost [7]
1 year ago
6

Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your

answer.
Mathematics
1 answer:
lilavasa [31]1 year ago
5 0

We have the equation:

y=a\cdot b^x

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}

Now, we use the point (2, 108/25) to calcualte b:

\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}

Then, we can write the equation as:

y=3\cdot(\frac{6}{5})^x

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Find the surface area of the following triangular prism. surface area=_________ ft²
Scorpion4ik [409]
  • Answer:

<em>312 ft²</em>

  • Step-by-step explanation:

<em>3 rectangles </em>

<em>2 triangles</em>

<em>4 yd = 12 ft</em>

<em>A = 4ft×12ft + 8ft×12ft + 10ft×12ft + 2×6ft×8ft/2</em>

<em>= 48ft² + 96ft² + 120ft² + 48ft²</em>

<em>= 312 ft²</em>

3 0
3 years ago
The area of a rectangle is 30 square root 3750 square inches, and the length is 3 square root 250 inches what is the width of th
Ann [662]

Answer:

width=10\sqrt{15}\ in

Step-by-step explanation:

-A rectangle's area is given by:

A=lw\\\\l=length\\w=width

Given A=30\sqrt{3750} and l=3\sqrt{250}, we substitute in the formula to solve for the width as follows:

A=lw\\\\30\sqrt{3750}=3\sqrt{250}\times w\\\\w=\frac{30\sqrt{3750}}{3\sqrt{250}}\\\\w=10\frac{\sqrt{3750}}{\sqrt{250}}\\\\=10\times \sqrt{\frac{3750}{250}}\\\\=10\sqrt{15}\ in

Hence , the rectangle's width is 10\sqrt{15}\ in

6 0
3 years ago
Plz answer quickly !!!!
SVETLANKA909090 [29]

Im pretty sure: 18 units

8 0
3 years ago
This is a continuous set of points in the coordinate plane. It can be, but is not always, straight.
castortr0y [4]

Answer:

Linear. While all linear equations produce straight lines when graphed, not all linear equations produce linear functions. In order to be a linear function, a graph must be both linear (a straight line) and a function (matching each x-value to only one y-value).

5 0
3 years ago
Which red triangle shows a 90° counterclockwise rotation of the blue triangle? Check all that apply. On a coordinate plane, a bl
Tcecarenko [31]

Question:

1) Blue triangle points; (-1, 4), (-5, 4), and (-1, 1)

Red triangle points; (-4, -1), (-1, -1). and (-4, -5)

2) Blue triangle points (1, 1), (4, 5), (4, 1)

Red triangle points; (-1, 1), (-1, 4). and (-5, 4)

3) Blue triangle points (0, 1), (4, 4), (4, 1)

Red triangle points; (-4, 1), (-4, 4). and (0, 1)

4) Blue triangle points (-5, 4), (-1, 4), (-1, 1)

Red triangle points; (1, 1), (4, 1). and (4, 5)

5) Blue triangle points (-2, 5), (4, 5), (4, 1)

Red triangle points; (-1, 4), (-5, 4). and (-5, -2)

Answer:

The correctly rotated red triangles are those of (1), (2), and (5)

Step-by-step explanation:

In a 90° counterclockwise rotation, every x and y points of the original triangle are switched while the y is turned negative, as shown in the following equation;

(x, y) to (-y, x)

Therefore, the triangles that undergo a 90° counterclockwise rotation are as follows;

1) Blue triangle points; (-1, 4), (-5, 4), and (-1, 1)

Red triangle points; (-4, -1), (-1, -1). and (-4, -5)

(-1, 4) → (-4, -1)

(-5, 4) → (-4, -5)

(-1, 1) → (-1, -1)

Correctly rotated 90° counterclockwise

2) Blue triangle points (1, 1), (4, 5), (4, 1)

Red triangle points; (-1, 1), (-1, 4). and (-5, 4)

(1, 1) → (-1, 1)

(4, 5) → (-5, 4)

(4, 1) → (-1, 4)

Correctly rotated 90° counterclockwise

3) Blue triangle points (0, 1), (4, 4), (4, 1)

Red triangle points; (-4, 1), (-4, 4). and (0, 1)

(0, 1) → (0, 1) ≠ (-1, 0)

(4, 4) → (-4, 4)

(4, 1) → (-4, 1)

Not correctly rotated 90° counterclockwise

4) Blue triangle points (-5, 4), (-1, 4), (-1, 1)

Red triangle points; (1, 1), (4, 1). and (4, 5)

(-5, 4) → (4, 5) ≠ (-4, -5)

(-1, 4) → (4, 1)

(-1, 1) → (1, 1)

Not correctly rotated 90° counterclockwise

5) Blue triangle points (-2, 5), (4, 5), (4, 1)

Red triangle points; (-1, 4), (-5, 4). and (-5, -2)

(-2, 5) → (-5, -2)

(4, 5) → (-5, 4)

(4, 1) → (-1, 4)

Correctly rotated 90° counterclockwise.

8 0
3 years ago
Read 2 more answers
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