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3 years ago

Help me if you’re a real one!

Mathematics

1 answer:

nataly862011 [7]3 years ago

8 0

The answer is B. You solve each inequality and you get x is greater than or equal to 1 and x<6 so those two are included in the interval of b. So the answer is B.

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Which expression is equivalent to 3 (6x1) for all values of x

Ilia_Sergeevich [38]

Answer:

THE VALUE OF X IS 18

Step-by-step explanation:

7 0

3 years ago

Select all numbers that are sulutions to the inequality w>5

sertanlavr [38]

<h3>W is any number greater than 5</h3>

<em>Because there is a sign of greater than between w and 5</em>

So, By this info we can say that; Option A, Option D, Option E are correct!

8 0

3 years ago

Read 2 more answers

WHICH INEQUILITY IS EQUIVALENT TO X-4<9

frez [133]

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Answer: $\textsf{x} < \textsf{13}$

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Given: $\textsf{x - 4} < \textsf{9}$

Find: $\textsf{The simplified inequality}$

Solution: In order to simplify the inequality we can simply add 4 to both sides which would isolate x.

<u>Add 4 to both sides</u>

$\textsf{x - 4 + 4} < \textsf{9 + 4}$

$\textsf{x} < \textsf{9 + 4}$

$\textsf{x} < \textsf{13}$

Therefore, an inequality that would be equivalent to the one that was provided in the problem statement is x < 13.

5 0

2 years ago

Read 2 more answers

Can someone please explain to me how to solve this equation?

Nikolay [14]

Answer:

first of all erase what u have written

Step-by-step explanation:

25-3x-5=2x+16+x
20-6x=16
6x=4
x=2/3

6 0

3 years ago

Which function has a removable discontinuity?

attashe74 [19]

If the function factors and the bottom term cancels, the discontinuity at the x-value for which the denominator was zero is removable, so the graph has a hole in it. After canceling, it leaves you with x – 7. Therefore x + 3 = 0 (or x = –3) is a removable discontinuity..

4 0

3 years ago