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3 years ago

Which of the following has the greatest density?

Mathematics

2 answers:

zvonat [6]3 years ago

7 0

Answer:

A

Explanation:
A) 30/3 = 10 g/c
B) 20/5 = 4 g/c
C) 50/10 = 5 g/c
D) 40/5 = 8 g/c

Alinara [238K]3 years ago

5 0

Answer:

The object with the greatest density is A with 10,000 kilograms per cubic meter.

Step-by-step explanation:

A=10000 kilogram/cubic meter

B=4000 kilogram/cubic meter

C=5000 kilogram/cubic meter

D=8000 kilogram/cubic meter

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Solve 3(4m - 6) = 12 and explain each step

Studentka2010 [4]

Distribute the 3 to 4m and 6. this makes 12m-18=12
now add 18 to both sides.
12m=30
now divide by 12
m=30/12

3 0

3 years ago

Find the circumference,<br> 18 ft

Marysya12 [62]

Answer:

56.549 feet

Step-by-step explanation:

Diameter. ft in m

18′0″ 56.55. 678.6 17.24

18′1″ 56.81.

18′2″ 57.07. 684.9

18′3″ 57.33. 688.0

18′4″ 57.60. 691.2

18′5″ 57.86. 694.3 17.64

18′6″ 58.12. 697.4 17.71

18′7″ 58.38 700.6 17.79

18′8″ 58.64 703.7 17.87

18′9″ 58.90. 706.9 17.95

18′10″ 59.17. 710.0 18.03

18′11″ 59.43. 713.1 18.11

5 0

2 years ago

How many terms dose the polynomial have 2x^9 + 3x^6 - x - 20?

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

2x^9 = 1

3x^6 = 2

- x - 20 = 3

6 0

3 years ago

A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the

zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

$d = \frac{1}{2} ({v-0})t$

$5.5= \frac{1}{2} (1.6v)$

The speed of the sprinter then become:

$v = 6.875 m/s$

Part (b)

Convert the weight of the sprinter to mass:

$m = \frac{w}{g}$

$m = \frac{706}{9.8}$

$m = 72 kg$

KE (Kinetic Energy) can then be calculated as:

$KE = \frac{1}{2} mv^{2}$

$KE = \frac{1}{2} (72)(6.875)^{2}$

$KE = 1701.56 J = 1.70 kJ$

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

$P = \frac{KE}{t} \\\$

$P = \frac{1701.56}{1.6}$

$P = 1063.48 W = 1.06 kW$

5 0

3 years ago

What expression is equivalent to 486-9+6+3^*2

sattari [20]

Answer:

The expression equivalent to 486-9+6+3^*2 is 500-7+6+5^*2

Step-by-step explanation:

486-9+6+3^*2 = 500-7+6+5^*2

486-9+6+9 = 500-7+6+25

486-24 = 500-38

462 = 462

4 0

2 years ago