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3 years ago

If someone helps me solve all of this I’ll give em 15-20 pts and mark brainiest ;)

Mathematics

1 answer:

shusha [124]3 years ago

6 0

Answer:

1. cell?

2. distinction

3. assumption

4. foliage

5. commission

6. dimension

7. considerable

8. membrane

9. cell

10. final

11. viewpoint

12. considerable

Step-by-step explanation:

You might be interested in

Law of cosines.Anyone good in Trigonometry?

marin [14]

Answer:

$c=11.8\ units$

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

$c^2=a^2+b^2-2(a)(b)cos(C)$

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

$a=3\ units\\b=10\ units$

$C=120^o$

substitute the given values

$c^2=3^2+10^2-2(3)(10)cos(120^o)$

$c^2=109-(60)cos(120^o)$

$c^2=109-(60)(-0.5))$

$c^2=109+30$

$c^2=139$

$c=11.8\ units$

3 0

3 years ago

Changle. Show all work. Round each length to the nearest tenth and each angle to the

Sedaia [141]

Answer:

Part 1) $BC=12.2\ units$

Part 2) $m\angle A=55^o$

Part 3) $m\angle C=35^o$

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=7^2+10^2$

$AC^2=149\\AC=12.2\ units$

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

$tan(A)=\frac{BC}{AB}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{10}{7}$

using a calculator

$m\angle A=tan^{-1}(\frac{10}{7})=55^o$

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

$m\angle A+m\angle C=90^o$ ----> by complementary angles

substitute the given value

$55^o+m\angle C=90^o$

$m\angle C=90^o-55^o=35^o$

8 0

3 years ago

Let f(x) = x + 8 and g(x) = x2 − 6x − 7. find f(g(2)). −7 −3 10 33 open study

Ray Of Light [21]

F(g(2))

g(x) = x^2 - 6x - 7
g(2) = 2^2 - 6(2) - 7
g(2) = 4 - 12 - 7
g(2) = -15

f(x) = x + 8
f(g(2) = f(-15) = -15 + 8 = -7 <==

ur answer is -7

6 0

3 years ago

Using this formula l=A 1/2 what is the length of one side of a square with an area of 1,936 square kilometers? (A is the area of

Vera_Pavlovna [14]

c.)44 kilometers

Answer:

Solution given:

let

length =L

and

Area =A

Now

we have

Area [A]=1936 square kilometers

now

As we know that

Area of square :length *length

A=l*l

A=l²

Substituting value of A

1936=l²

doing square root on both side

$\sqrt{1936}=\sqrt{l²}$

we get

l= $\sqrt{2*2*2*2*11*11}$

l=2*2*11

l=44 kilometers

the length of one side of a square is 44 kilometers.

6 0

3 years ago

A system of equations has 1 solution. If 4x – y = 5 is one of the equations, which could be the other equation?

postnew [5]

Answer:

D: 2y = 8x - 10

Step-by-step explanation:

A: y = 4x + 5. This has a slope of -4 Yes it could work.

B: y = 4x - 5. No It does not work

C: 2y = 8x - 10. The slope is 8/2 = 4. So No it could not work.

D: -2y = 8x - 10. The slope is 8/-2 = -4. Yes This Does work! :)

8 0

3 years ago